find first& end of array
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Stephen23
2022-5-20
S = [0,1,5,2,0,0,0,9,3,50,53,0,0,5,7,4]
X = diff([0;S(:)]==0)<0 | diff([S(:);0]==0)>0;
V = S(X)
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更多回答(2 个)
the cyclist
2022-5-20
I expect someone will post a more elegant method, but I think this does what you want
S=[0 1 5 2 0 0 0 9 3 50 53 0 0 5 7 4];
first = S(diff([0 S]) == S & S~=0);
last = S(diff([S 0]) ==-S & S~=0);
firstLast = [first; last];
output = firstLast(:)'
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Image Analyst
2022-5-20
Here's a different way:
S=[0 1 5 2 0 0 0 9 3 50 53 0 0 5 7 4];
S2 = [0,S,0];
indexes = sort([strfind(S2~=0, [0 1]) + 1, strfind(S2~=0, [1,0])])
S3 = S2(indexes)
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