row that increases more every element

Hello,
I was wondering how I would make an array that increases more every element
for example:
given lets say n=randi([10 20], 1);
how would i have vect1 = 9, 16, 25, 36, ... n: so bascially increasing by +2 every element starting at 9

3 个评论

Your limit of numbers is [10,20] how you expect 25, 36 .. ?
Your example increases by 9 each time, not by 2?
Are you wanting to start with the fixed value 9 and use the random number to determine the number of terms??
it increases 7 then 9 then 11 then 13 ect.. so starting at 9 increases by 7 + 2* (what ever element you are on - 1)

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 采纳的回答

RozuSolo
RozuSolo 2022-5-20
nvm I got it.. It's just two vectors multiplied to each other [3, n] .* [3, n] so each element is 3x3 4x4 5x5 6x6 ect...

更多回答(1 个)

Here's my guess:
A = randi([10 20], 1,10)
A = 1×10
11 18 15 16 19 13 12 12 12 15
B = cumsum(A) % cumulative sum of A
B = 1×10
11 29 44 60 79 92 104 116 128 143

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