integral2 with parameters

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Stanislav Kogan
Stanislav Kogan 2022-5-20
编辑： Torsten 2022-5-20
i am trying to solve this king of integral using matlab how do i do it?
  1 个评论
Torsten
Torsten 2022-5-20
编辑：Torsten 2022-5-20
The integral does not exist.
In the limits from a to b (0<=a<b<R), it equals
log(sqrt((R^2-a^2)/(R^2-b^2)))

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回答（1 个）

Charles Barthelmebs
If you search the analytical solution you can try this:
syms r;
f = r/(R^2-r^2)
int(f,x,0,R)
but for numerical, you can use
integral(function,Xmin,Xmax)

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