help on graph (w/o common matrix plotting built-in functions)

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Patrick Laux
Patrick Laux 2022-5-20
编辑： Voss 2022-5-21
Dear all,
based on a matrix of zeros and ones, let's say 10 x 365 (10 years a 365 days), I would like to plot a '-' for a one and leave the position blank ' ' for a zero.
Thus, the graph should e.g. look like:
....
------ --- --- ---- ---- ------ ----- --
-------- ------ --------------- -----------
------ -- ---------- --------- ---------
----- --------------- ------ ---------- -
.....
Any hint appreciated.

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采纳的回答

Les Beckham
Les Beckham 2022-5-20
Ran in:
In that case, maybe something like this will get you close.
A = randi(2,10,365)-1;
x = 1:size(A,2);
y = size(A,1):-1:1;
for i = 1:size(A,1)
A(i,:) = A(i,:)*y(i);
end
A(A==0) = NaN;
for i = 1:size(A,1)
line(x, A(i,:), 'Marker', '_', 'linestyle', 'none', 'MarkerSize', 0.1)
end

更多回答（5 个）

Les Beckham
Les Beckham 2022-5-20
Ran in:
A = randi(2,10,365)-1
A = 10×365
1 1 1 1 1 1 1 1 0 1 0 1 1 0 1 1 0 0 0 0 0 0 1 1 0 1 1 0 1 0 1 0 0 1 0 1 1 0 0 0 1 0 0 1 0 0 1 1 0 0 0 0 0 1 1 1 1 1 0 0 0 1 1 1 1 0 1 1 0 1 0 1 1 1 1 0 1 1 0 0 0 0 1 1 0 0 0 1 1 1 1 0 0 0 1 0 0 1 0 1 1 1 1 0 1 1 0 0 0 0 1 0 0 0 1 1 1 1 0 0 0 1 0 0 0 0 1 1 0 1 0 0 0 1 1 0 1 1 0 0 0 0 1 1 1 0 0 1 1 1 0 0 0 1 0 0 1 0 1 0 1 1 0 0 1 1 0 0 1 1 1 0 0 0 1 1 0 1 0 1 1 0 1 0 0 1 0 1 0 0 1 0 1 0 0 1 1 0 1 0 1 0 0 0 0 0 0 0 1 1 1 1 1 0 0 1 1 1 1 1 1 1 0 0 1 0 1 1 0 0 0 1 1 0 1 0 0 1 1 0 1 0 0 1 0 0 0 0 0 0 1 0 1 1 0 0 1 1 1 1 1 0 0 0 0 0 1 0 0 1 0 0 1 1 1 0 1 1 1 0 0 1 0 1 0 1 0 0 1 0 0 0 1 1 1 0 1 0 0 1
str = repmat(' ', size(A));
str(A==1) = '-';
disp(str)
-------- - -- -- -- -- - - ------ - --- --- -- - - - - - -- --- - --- - -- - -- -- -- --- ---- -- --- ---- - - - - -- - ------- - - - - - ---- --- - -- --- - -- - --- - -- - - - ----- --- ---- ------- - - - - --- - ------- ---- -- -- - - - -- - -- - - - - -- - ---- -- -- - -- --- - - - -- - - -- ----- - - ---- ---- -- - -- ------- --- - - - - --- ---- - - - - - -- - - ---- - - - ------ ------ - --- --- -- -- - - - -- - - -- --- -- - ----- -- - - -- ---- ---- - -- - - - --- - - -- - - -- - -- - - - - - -- -- - --- -- --- - -- - - - --- - -- -- - ---- -- - ---- -- -- --- --- -- -- - - - ----- ---- - - ---- - - ---- - --- - -- --- -- - --- --- ----- -- -- --- - -- - --- - --- - --- --- ------ -- - -- - - ----- - --- ----- -- - - - ------ ---- - - -- --- ----- - - --- -- -- - - ----- - - - - ----- - - - ----- -- - - - - - ---- -- - ---- --- - ------ - - -- - -- ---- - - ---- --- ---- --- - --- - - - - - -- ------ ---- --- - --- - -- ------ --- -- -- - -- -- - ----- --- - - - --------- - - ---- - --- - - -- ----- --- --- - -------- ---- - - ------- -- - - ---- - - -- - - ---- --- - - - - - - -- - -- -- --- --- - -- - -- ---- - - -- - --- -- - - --- --- - - - - - ----- ----- -- - -- -- --- - -- -- - - - ---- - -- --- - -- - -- -- ----- ---------- - ---- -- -- - -- - - - ---- ----- - --- - -- - ------ - ---- -- - - - - - - -- - --- --- -- ---- - - - - - - - - - - - -- -- --- -- - ---- - --- - ---- - - - -- ---- - --- - - - --- - ----- -- ---- ---- - - ----- -- - - - -- - - --- - -- -- - - - --- -- - - -- - -- - - - -- -- - - -- --- - - - - - - - - ---- - -- - ----- - --- - - - - - -- - -- - --- -- - - - - -- --- --- - -- --- -- -- ---- --- - - - - - - -- - - -- - ----------- - - - ------ - - - --- -- - - - --- -- -- - - --- - - -- -- ---- - ---- - -- - ------- - - - - ---- ----- -- ---- - ---- ---- - -- - - - -- - - - - - - --- -- - --- ---- -- ------- -- -- - - - - - - - --- - -- --- --- - - - ----- - -- - -- - - --- ------- - -- -- - -- --- - - -- --- --- -- --- -- ------ -- - --- --- -- - ---- - - -- ---- -- - --- - -- - - - --- -- --------- -- - --- - - - --- - ---- -- - - --- - - -- ----- - - -- - --- --- - - - - - --- - -- ---- -- --- - -- -- - --- ------- - -- --- -- - ------- - - - - - - - -- ----- - - - - - -- - - - -- - - -- -- ---- -- -- -- -- - --- -- - -- - --- - ------ - - ---- -- -- - ----- - - - -- -- - -- - - ----- - -- - --- - --- - - - - -- -- --- - - - -- - --- --- --- - ---- - - - ---- - ---- -- - - -- - -- -- - -- ---- - - - - - - --- --- - - - - --- - -- -- - --- - --- -- - ---- ------- -- --- --- - - -- - - - - - -- - - ---- -- -- --- -- --- - - - --- - -- - -- --- - --- -- - - ---- - - - --- - - -- ---- --- - -- -- -- -- -- --- --- - - -- -- --- --- ---- -- -- ----- - -- - - -- ----- - -----
  3 个评论
显示 1更早的评论
Les Beckham
Les Beckham 2022-5-20
@Steven Lord
How clever! I'm suprised that that works. I would have never thought to index into a 1x2 array with a larger index array.
Steven Lord
Steven Lord 2022-5-21
The size of the index array doesn't matter for linear indexing. What matters are the values in that array.

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Patrick Laux
Patrick Laux 2022-5-20
excellent already, but actually I thought about having a real figure with xaxis and yaxis. Sorry that I was not very clear here.
  1 个评论
Steven Lord
Steven Lord 2022-5-21
Ran in:
A = randi([0 1], 5, 5)
A = 5×5
1 0 0 1 1 1 1 1 1 1 1 0 1 0 1 0 1 1 1 0 0 1 0 1 1
spy(A)
If you really want dashes:
figure
spy(A, '_')

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DGM
DGM 2022-5-20
编辑：DGM 2022-5-20
In the spirit of ridiculousness, here is my attempt:
% random binary data
data = randi([0 1],10,10)
data =
1 1 0 0 1 1 1 1 0 0
0 0 0 1 0 1 1 1 1 1
0 0 0 1 1 0 0 0 1 0
1 1 1 1 0 1 0 0 1 0
0 1 0 1 0 1 1 0 1 1
0 1 0 1 0 0 1 1 1 0
0 0 1 0 1 0 1 0 0 0
0 0 0 0 0 1 1 0 0 1
1 0 0 0 1 1 0 1 0 1
0 1 1 0 0 1 0 1 0 1
% convert to char data (space and full-width crossbar)
charmap = char([32 196]);
chardata = charmap(data+1)
chardata =
10×10 char array
'ÄÄ ÄÄÄÄ '
' Ä ÄÄÄÄÄ'
' ÄÄ Ä '
'ÄÄÄÄ Ä Ä '
' Ä Ä ÄÄ ÄÄ'
' Ä Ä ÄÄÄ '
' Ä Ä Ä '
' ÄÄ Ä'
'Ä ÄÄ Ä Ä'
' ÄÄ Ä Ä Ä'
% construct an image by flowing char glyphs into a rectangular box
charsize = [8 8]; % depends on the selected font
datasize = size(chardata);
tsize = [NaN datasize(2)*charsize(2)+charsize(2)/2];
outpict = textblock(chardata(:)',tsize,'font','compaq-8x8','tightwidth',true,'hardbreak',true);
% display the image with character-centered tickmarks
xrange = 0.5:datasize(1)+0.5;
yrange = 0.5:datasize(2)+0.5;
imagesc(xrange,yrange,1-outpict)
colormap(gray)
Alternatively, instead of using a full crossbar, you can just use
charmap = ' -';
and get
Bear in mind those are different random data. The point is that the bars don't touch.
This uses a few tools from MIMT, namely textblock() and imstacker().
Patrick Laux
Patrick Laux 2022-5-21
great answers! Thank you very much, very helpful
Voss
Voss 2022-5-21
编辑：Voss 2022-5-21
Ran in:
data = randi([0 1],10,30)
data = 10×30
0 0 1 1 0 1 1 1 1 0 1 0 1 0 0 1 1 1 0 1 1 1 1 1 0 1 1 0 0 0 0 1 1 0 1 0 1 1 1 1 1 0 0 1 1 0 0 1 0 1 1 1 1 0 1 0 0 0 1 0 1 1 1 1 0 1 1 0 0 0 0 0 1 1 0 1 1 0 0 1 0 1 0 0 1 0 0 1 1 1 0 1 1 0 1 0 0 1 0 0 0 0 1 1 0 1 0 1 0 0 0 1 1 1 1 1 1 0 0 1 0 1 0 1 0 1 0 1 0 1 1 0 0 1 1 1 0 1 1 1 1 0 0 1 0 1 0 0 0 1 0 1 1 0 0 0 1 1 1 1 0 0 0 0 0 0 0 1 1 0 1 1 0 0 1 0 1 1 1 0 0 0 0 1 1 0 1 1 0 0 0 0 0 0 0 0 0 1 1 1 0 1 1 0 1 0 0 0 1 1 0 1 0 1 1 1 0 0 0 0 0 0 0 1 1 0 1 0 1 1 0 0 0 0 0 0 0 1 0 1 0 1 0 1 1 0 0 0 0 0 1 1 0 1 0 0 0 1 1 1 0 1 1 0 1 1 0 1 1 1 1 1 0 0 0 1 0 1 1 0 1 1 0 0 1 1 1 0 0 0 0 1 0 1 0 0 1 1 0 1
imshow(1-data)

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