Reshape Nx1 struct with field of Mx1 elements to N*Mx1 vector

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Sabyrzhan Tasbolatov
评论： Stephen23 2022-5-22
I have a struct A of [1000x1] size. There is a field "bar" which has [100x1] elements.
I want to have 1 variable, let's say B, which will be [1000*100x1] of "bar" elements.
How can I do it without iterating a struct and appending on some prepared zeroed vector? Can reshape do it?

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采纳的回答

Bruno Luong
Bruno Luong 2022-5-22
编辑：Bruno Luong 2022-5-22
Something like
B = cat(1,A.bar)

更多回答（1 个）

MJFcoNaN
MJFcoNaN 2022-5-22
Ran in:
This is an example:
bar=rand(100,1)
bar = 100×1
0.4600 0.1687 0.4194 0.2287 0.7427 0.7976 0.8690 0.4868 0.9914 0.4464
A=struct;
A.bar=bar;
% copy A.bar to all 1000 elements
A(2:1000,1)=A(1)
A = 1000×1 struct array with fields:
bar
% table is a good intermediate form
tbl=struct2table(A);
B=cell2mat(cellfun(@transpose, tbl.bar, 'UniformOutput', false))
B = 1000×100
0.4600 0.1687 0.4194 0.2287 0.7427 0.7976 0.8690 0.4868 0.9914 0.4464 0.1298 0.0337 0.5265 0.2551 0.7338 0.6966 0.2969 0.3447 0.0830 0.7853 0.9779 0.2714 0.3507 0.4244 0.3516 0.3386 0.8395 0.6153 0.2840 0.6013 0.4600 0.1687 0.4194 0.2287 0.7427 0.7976 0.8690 0.4868 0.9914 0.4464 0.1298 0.0337 0.5265 0.2551 0.7338 0.6966 0.2969 0.3447 0.0830 0.7853 0.9779 0.2714 0.3507 0.4244 0.3516 0.3386 0.8395 0.6153 0.2840 0.6013 0.4600 0.1687 0.4194 0.2287 0.7427 0.7976 0.8690 0.4868 0.9914 0.4464 0.1298 0.0337 0.5265 0.2551 0.7338 0.6966 0.2969 0.3447 0.0830 0.7853 0.9779 0.2714 0.3507 0.4244 0.3516 0.3386 0.8395 0.6153 0.2840 0.6013 0.4600 0.1687 0.4194 0.2287 0.7427 0.7976 0.8690 0.4868 0.9914 0.4464 0.1298 0.0337 0.5265 0.2551 0.7338 0.6966 0.2969 0.3447 0.0830 0.7853 0.9779 0.2714 0.3507 0.4244 0.3516 0.3386 0.8395 0.6153 0.2840 0.6013 0.4600 0.1687 0.4194 0.2287 0.7427 0.7976 0.8690 0.4868 0.9914 0.4464 0.1298 0.0337 0.5265 0.2551 0.7338 0.6966 0.2969 0.3447 0.0830 0.7853 0.9779 0.2714 0.3507 0.4244 0.3516 0.3386 0.8395 0.6153 0.2840 0.6013 0.4600 0.1687 0.4194 0.2287 0.7427 0.7976 0.8690 0.4868 0.9914 0.4464 0.1298 0.0337 0.5265 0.2551 0.7338 0.6966 0.2969 0.3447 0.0830 0.7853 0.9779 0.2714 0.3507 0.4244 0.3516 0.3386 0.8395 0.6153 0.2840 0.6013 0.4600 0.1687 0.4194 0.2287 0.7427 0.7976 0.8690 0.4868 0.9914 0.4464 0.1298 0.0337 0.5265 0.2551 0.7338 0.6966 0.2969 0.3447 0.0830 0.7853 0.9779 0.2714 0.3507 0.4244 0.3516 0.3386 0.8395 0.6153 0.2840 0.6013 0.4600 0.1687 0.4194 0.2287 0.7427 0.7976 0.8690 0.4868 0.9914 0.4464 0.1298 0.0337 0.5265 0.2551 0.7338 0.6966 0.2969 0.3447 0.0830 0.7853 0.9779 0.2714 0.3507 0.4244 0.3516 0.3386 0.8395 0.6153 0.2840 0.6013 0.4600 0.1687 0.4194 0.2287 0.7427 0.7976 0.8690 0.4868 0.9914 0.4464 0.1298 0.0337 0.5265 0.2551 0.7338 0.6966 0.2969 0.3447 0.0830 0.7853 0.9779 0.2714 0.3507 0.4244 0.3516 0.3386 0.8395 0.6153 0.2840 0.6013 0.4600 0.1687 0.4194 0.2287 0.7427 0.7976 0.8690 0.4868 0.9914 0.4464 0.1298 0.0337 0.5265 0.2551 0.7338 0.6966 0.2969 0.3447 0.0830 0.7853 0.9779 0.2714 0.3507 0.4244 0.3516 0.3386 0.8395 0.6153 0.2840 0.6013
  1 个评论
Sabyrzhan Tasbolatov
Sabyrzhan Tasbolatov 2022-5-22
Thanks, I'm going to use cat as it's faster
Elapsed time is 0.001430 seconds.
I've also tried your option, it takes:
Elapsed time is 0.020119 seconds.

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