For Loop in 3D Array

16 次查看(过去 30 天)
For 2D arrays, the operation that I want to execute is:
a = rand(3,3);
for i = 1:numel(a)
for j = 1:numel(a)
out(i,j) = (a(i) - a(j)) / (a(i) + a(j));
end
end
Which will turn the out into a skew-symmetric matrix. Now I want to perform the same operation instead the matrix is in 3D, how can I do that? The speed is important since my original matrix is (100,100,726). Thanks!

采纳的回答

Dyuman Joshi
Dyuman Joshi 2022-5-31
编辑:Dyuman Joshi 2022-5-31
a = rand(3,3,4);
for k=1:size(a,3)
y=a(:,:,k);
for i=1:size(y,1)
for j=1:size(y,2)
out(i,j,k)=(y(i) - y(j))/(y(i) + y(j));
end
end
end
out
out =
out(:,:,1) = 0 0.6498 -0.1418 -0.6498 0 -0.7248 0.1418 0.7248 0 out(:,:,2) = 0 -0.6166 -0.5396 0.6166 0 0.1154 0.5396 -0.1154 0 out(:,:,3) = 0 0.1018 0.1400 -0.1018 0 0.0387 -0.1400 -0.0387 0 out(:,:,4) = 0 0.2123 0.1857 -0.2123 0 -0.0277 -0.1857 0.0277 0
  2 个评论
Dyuman Joshi
Dyuman Joshi 2022-5-31
It will be skew-symmetric matrix. I have made an edit, take a look at it again.
MarshallSc
MarshallSc 2022-5-31
Thanks, yeah, changing the i and j indices from 1:size(y,1) to numel(y) would do the trick. Thanks again!

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Get Started with MATLAB 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by