Indefinite integral for a step function with variable number of steps

2 次查看（过去 30 天）
Mohammad Shojaei Arani
评论： Mohammad Shojaei Arani 2022-6-1
Hello friends,
I have a function handle which is defined by interp1. Is there a way to find its indefinite integral?
For instance
x0=[1 2 5 7 10];y0=[2 1 3 2]; f=@(x)interp1(x0,y0,x,'previous');
Please note the above example is just a simple case (I know how to handle this easy case). My function is a step function with many steps where the number of steps are not known to me beforehand. So, in general my function is defined by f=@(x)interp1(mesh,c,x,'previous'); where mesh is my x-data, c is a vector of steps or y-data. How to find the indefinite integral of this function?
Thanks in advance!
Babak

请先登录，再回答此问题。

采纳的回答

Torsten
Torsten 2022-6-1
The definite integral between a and b where mesh(1) <= a < b <= mesh(end) can be computed as for every other function as
value_integral = integral(f,a,b)
where
f = @(x)interp1(mesh,c,x,'previous')
  3 个评论
显示 1更早的评论
Torsten
Torsten 2022-6-1
y0 has only 4 elements. It must be of the same size as x0 - thus have 5 elements.

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Linear Algebra 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by