Splitting columns based on comma

14 次查看（过去 30 天）
greenyellow22
greenyellow22 2022-6-1
评论： greenyellow22 2022-6-6
Hey everyone, I have a table (raw) with several columns, one of them is 'Position' (see below) which contains different coordinates. Some rows are blank (''). I want to split the coordinates based on the comma between them and put them seperately back to the 'raw' table.
raw.Position =
''
''
''
'(-6.9, 4.8, 68.4)'
'(-8.5, 3.1, 18.0)'
'(13.5, 2.5, 70.1)'
''
''
I tried the following
P = raw.Position
new = regexp(P, ',','split');
raw.a = P(:,1); Error: Index in position 2 exceeds array bounds. Index must not exceed 1.
raw.b = P (:,2);
raw.c = P (:,3);
but the 'new' table saved the splitted coordinates in 1x3 cells, so they could not be transfered back to the 'raw' table (I think that's the problem). Also, I wanted to remove the brackets as well from the coordinates which did not work either.. Any help appreciated!
new =
''
''
''
1x3 cell
1x3 cell
1x3 cell
''
''

请先登录，再回答此问题。

采纳的回答

Stephen23
Stephen23 2022-6-1
Ran in:
raw.Position = {'';'';'';'(-6.9, 4.8, 68.4)';'(-8.5, 3.1, 18.0)';'(13.5, 2.5, 70.1)';'';''};
tmp = sscanf(sprintf('%s',raw.Position{:}),'(%f,%f,%f)',[3,Inf]).';
raw.a = tmp(:,1);
raw.b = tmp(:,2);
raw.c = tmp(:,3)
raw = struct with fields:
Position: {8×1 cell} a: [3×1 double] b: [3×1 double] c: [3×1 double]
  3 个评论
显示 1更早的评论
Stephen23
Stephen23 2022-6-3
Ran in:
aw.Position = {'';'';'';'(-6.9, 4.8, 68.4)';'(-8.5, 3.1, 18.0)';'(13.5, 2.5, 70.1)';'';''};
fnh = @(t) sscanf(t,'(%f,%f,%f)',[1,3]);
V = cellfun(fnh,aw.Position,'uni',0)
V = 8×1 cell array
{0×0 double } {0×0 double } {0×0 double } {[-6.9000 4.8000 68.4000]} {[ -8.5000 3.1000 18]} {[13.5000 2.5000 70.1000]} {0×0 double } {0×0 double }
Stephen23
Stephen23 2022-6-3
Ran in:
aw.Position = {'';'';'';'(-6.9, 4.8, 68.4)';'(-8.5, 3.1, 18.0)';'(13.5, 2.5, 70.1)';'';''};
fnh = @(t) sscanf(t,'(%f,%f,%f)',[1,3]);
V = cellfun(fnh,aw.Position,'uni',0);
V(cellfun(@isempty,V)) = {nan(1,3)};
M = vertcat(V{:})
M = 8×3
NaN NaN NaN NaN NaN NaN NaN NaN NaN -6.9000 4.8000 68.4000 -8.5000 3.1000 18.0000 13.5000 2.5000 70.1000 NaN NaN NaN NaN NaN NaN

请先登录，再进行评论。

更多回答（2 个）

greenyellow22
greenyellow22 2022-6-3
But with that I would end up having the coordinates in one column all together again, and not have them splitted into three columns... :/
greenyellow22
greenyellow22 2022-6-3
Thanks!
Instead of aw.Position = {'';'';'';'(-6.9, 4.8, 68.4)';'(-8.5, 3.1, 18.0)';'(13.5, 2.5, 70.1)';'';''}, I wrote
XY = aw.Position;
fnh = @(t) sscanf(t,'(%f,%f,%f)',[1,3]);
V = cellfun(fnh,XY,'uni',0);
V(cellfun(@isempty,V)) = {nan(1,3)};
M = vertcat(V{:})
(aw is a table already existing, where Position is just one column with more rows and coordinates than the example I gave).
but then I get the error message:
Error using vertcat
Dimensions of arrays being concatenated are not consistent.
I'm sorry, I just don't have enough transfer knowledge to adapt your commands accordingly.
  4 个评论
显示 2更早的评论
Stephen23
Stephen23 2022-6-4
编辑：Stephen23 2022-6-5
"Not sure if that makes sense"
Yes, it makes sense. As I already wrote in my earlier comment, the cause is probably that your data differ in some way to the example data that you gave. Because you did not upload your actual data in a mat file by clicking the paperclip button, I cannot investigate this for you. If you do upload your data, then I can investigate it.
greenyellow22
greenyellow22 2022-6-6
I understand but unfortunately, I cannot upload the data. But I have a table of 5 columns and one column contains the coordinates (23420x1 cells), whereby some cells/ rows are empty and some contain the coordinates (e.g. '(-6.9, 4.8, 68.4)'). So for all cells containing coordinates I want to split the coordinates into three and enter these seperately into three different new columns added to the table (with the empty cells staying empty). If writing the commands is impossible without the data, then I understand and thank you anyway for your prior help :-)

请先登录，再进行评论。

类别

在 Help Center 和 File Exchange 中查找有关 Logical 的更多信息

标签

产品


版本

R2022a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by