Intermediate step return ```InF``` while using exp

2022 6 3
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更新时间：2022 6 3
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```
aa=8e+05;
bb=1e+06;
tf=0.002;
temp=(-(bb*exp(bb*tf)-aa*exp(aa*tf))*exp(-bb*tf-aa*tf)+bb-aa)
```
Output is InF
I believe the InF comes from exp(bb*tf) and exp(aa*tf)
What should do to make this work? Thank you

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Walter Roberson
Walter Roberson 2022-6-3
编辑：Walter Roberson 2022-6-3

0 个投票

aa=sym(8e+05) ;
bb =sym(1e+06) ;
tf =sym(0.002);
temp = simplify( (-(bb*exp(bb*tf)-aa*exp(aa*tf))*exp(-bb*tf-aa*tf)+bb-aa))
The answer involves two terms with exp() of -2000 and -1600, plus a constant 2000. The exp() terms are so small that they have no practical effect on the constant. The larger of the two exp() is roughly -1e-689

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