Intermediate step return ```InF``` while using exp

2022 6 3
1 个回答
回答已采纳
更新时间：2022 6 3
5 次查看（30 天）

0 个投票

```
aa=8e+05;
bb=1e+06;
tf=0.002;
temp=(-(bb*exp(bb*tf)-aa*exp(aa*tf))*exp(-bb*tf-aa*tf)+bb-aa)
```
Output is InF
I believe the InF comes from exp(bb*tf) and exp(aa*tf)
What should do to make this work? Thank you

请先登录，再回答此问题。

 采纳的回答

Walter Roberson
Walter Roberson 2022-6-3
编辑：Walter Roberson 2022-6-3

0 个投票

aa=sym(8e+05) ;
bb =sym(1e+06) ;
tf =sym(0.002);
temp = simplify( (-(bb*exp(bb*tf)-aa*exp(aa*tf))*exp(-bb*tf-aa*tf)+bb-aa))
The answer involves two terms with exp() of -2000 and -1600, plus a constant 2000. The exp() terms are so small that they have no practical effect on the constant. The larger of the two exp() is roughly -1e-689

更多回答（0 个）

类别

在 帮助中心 和 File Exchange 中查找有关 Programming 的更多信息

产品

版本

R2021b

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by