Time Vector in X axis Plotting

2022 6 3
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更新时间：2022 6 3
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aa = {rand(482,5) , rand(493,5)};
t = linspace(0, 20,975 ); % Generating Time Vector Series
Now how can I plot the cell data "aa" while keeping Time vector Series will lie in the X-axis?
Thanks in ADVANCE !!

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Voss
Voss 2022-6-3
Ran in:

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Ran in:
aa = {rand(482,5) , rand(493,5)};
t = linspace(0, 20,975 ); % Generating Time Vector Series
n_aa = cellfun(@(x)size(x,1),aa)
n_aa = 1×2
482 493
plot(t(1:n_aa(1)),aa{1})
hold on
plot(t(n_aa(1)+(1:n_aa(2))),aa{2})

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Amit Chakraborty
Amit Chakraborty 2022-6-3
Thank you for the answer.
But what will happen if I have the cell array, aa ={ 3 or more cell }. Then How I shall plot?
plot(t(1:n_aa(1)),aa{1})
hold on
plot(t(n_aa(1)+(1:n_aa(2))),aa{2})
Voss
Voss 2022-6-3
Ran in:
Ran in:
% this time, I'll start with n_aa
n_aa = randi([480 500],1,7)
n_aa = 1×7
481 488 490 489 500 489 497
% and generate random aa from n_aa
aa = arrayfun(@(x)rand(x,5),n_aa,'UniformOutput',false)
aa = 1×7 cell array
{481×5 double} {488×5 double} {490×5 double} {489×5 double} {500×5 double} {489×5 double} {497×5 double}
% t is defined as before (but with more elements)
t = linspace(0, 20, sum(n_aa));
% generate t_idx to help with plotting
t_idx = cumsum([0 n_aa])
t_idx = 1×8
0 481 969 1459 1948 2448 2937 3434
% plot in a loop this time
hold on
for ii = 1:numel(aa)
plot(t(t_idx(ii)+1:t_idx(ii+1)),aa{ii})
end
Voss
Voss 2022-6-3
You're welcome!

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