set count numbers of rows in a uitable

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Cristian Martin 2022-6-6

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1734625-set-count-numbers-of-rows-in-a-uitable

评论： dpb 2022-6-6

Hi,

I'm trying to modify the first column number for each row( 1 2 3 ...) in an uitable based of each entry from another uitable:

D=get(handles.uitable1,'Data');%GETTING DATA FROM FIRST TABLE

Index=get(handles.uitable1,'UserData');

a = D(Index.Indices(:,1), :);

old_data=get(handles.uitable4,'Data'); %GETTING OLD DATA FROM SECOND TABLE

data_azi = datetime;

data_azi.Format = 'MM.dd.yyyy';

a = array2table(a);

a.a1 = 1;

a.a4 = a.a2;

a.a2 = char(data_azi);

a.a2 = {a.a2};

a = table2cell(a);

new_data = [old_data; a];

new_data = array2table(new_data);

numarnou = height(new_data);% GET HEIGHT OF OLD AND NEW TABLE

new_data.new_data2 = numarnou;% MODIFY THE RESULT OF ROWS HEIGHTS IN FIRST COLUMN

new_data.new_data2 = {new_data.new_data2};

new_data = table2cell(new_data);

set(handles.uitable4, 'Data',new_data); %SETTING DATA FROM FIRST TABLE

The error:

To assign to or create a variable in a table, the number of rows must match the height of the table.

Where am I wrong?

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dpb 2022-6-6

在 MATLAB Online 中打开

new_data = [old_data; a];

You've catenated more data onto the existing from uitable1 so the height is the total of both tables.

The uitable object is not dynamically resized; I've not used it extensively, but I think the only way to add data entails recreating a new table. Seems klunky, but I've not seen anything that implies there is an addrow functionality.

Cristian Martin 2022-6-6

Got it, thanks !

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采纳的回答

Cristian Martin 2022-6-6

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1734625-set-count-numbers-of-rows-in-a-uitable#answer_979970

I have found the solution:

old_data=get(handles.uitable4,'Data');

old_data = array2table(old_data);

nr_crt = height(old_data); %HERE I GET THE HEIGHT OF OLD DATA

old_data = table2cell(old_data);

data_azi = datetime;

data_azi.Format = 'MM.dd.yyyy';

a = array2table(a);

a.a1 = 1 + nr_crt; %HERE I ADD THE HEIGHT OF OLD DATA TO THE FIRST COLUMN OF THE NEXT ROW IN SECOND TABLE

a.a4 = a.a2;

a.a2 = char(data_azi);

a.a2 = {a.a2};

a = table2cell(a);

new_data = [old_data; a];

set(handles.uitable4, 'Data',new_data);

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Cristian Martin 2022-6-6

It;s weird to accept my answer , no?

dpb 2022-6-6

It's OK. I now recall I had seen that before but I just couldn't recall it before...I hadn't used the uitable enough to recall it, but I shoulda'.

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