generate matrix by for loop
显示 更早的评论
A=[1 -10 4
0 -2 7
5 1 9]
I need to get
A=[1 0 -10 0 4
0 0 -2 0 7
5 0 1 0 9]
by for loop
1 个评论
David Meissner
2022-6-6
I would look into "Indexing with a Single Index" here: https://www.mathworks.com/help/matlab/math/array-indexing.html
采纳的回答
Don't need a loop.
A = [1 -10 4
0 -2 7
5 1 9];
B = zeros(size(A,1),2*size(A,2)-1); % allocate
B(:,1:2:end) = A % fill in nonzero columns
5 个评论
Mako
2022-6-6
Mako
2022-6-6
The above code doesn't depend on the size of A. A can be any 2D array.
A loop is not necessary. If you want to use a loop anyway, you can preallocate the output array and assign data columnwise.
A = [1 -10 4
0 -2 7
5 1 9];
B = zeros(size(A,1),2*size(A,2)-1); % allocate
cv = 1:2:size(B,2); % column indices of the output array
for c = 1:size(A,2)
B(:,cv(c)) = A(:,c); % fill in nonzero columns
end
B
Mako
2022-6-6
DGM
2022-6-6
Either answer will zero-pad columns regardless of the size or contents of A.
If you're trying to describe a particular generalized relationship between input and output, you'll have to clarify with both inputs and outputs for your example.
更多回答（0 个）
类别
在 帮助中心 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息
Translated by 
