How to store values in summation for loop?
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Hi, i dont know how to store values for each iteration? It keeps showing up as the same values for example iteration 1 =[50 50 50], iteration 2=[100 100 100]
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/1026055/image.jpeg)
2 个评论
John D'Errico
2022-6-9
A picutre of your code does nothing, because we cannot use that code. Just paste in the code as text. Why do you want to make it more difficult to get help?
回答(2 个)
Sajid Afaque
2022-6-9
编辑:Sajid Afaque
2022-6-9
you need to create an array to store your results,
currently with this approach you are over-writing your results in variable s after each iteration
and also here s is an array of zeros and you are adding scalar to entire array in each iteration,
so finally you will have results obtained in final iteration and all the values would be equal
k=1:5;
s=zeros(1,length(k));
store_values = []; %create a where where you need to store results
for i= length(k)
store_value{i}=s(i)+(((-1).^k(i)).*(k(i).^(k(i)+1)))/(2.^k(i)) %focus on left side of equate, modify the right side of the equation as you need
end
%try this should work
0 个评论
John D'Errico
2022-6-9
编辑:John D'Errico
2022-6-9
You understand how to index a variable, thus k(i). But when you write this:
s = s + (stuff)
It increments ALL elements of the vector s.
Is there a good reason why you did not try:
s(i) = s(i) + (stuff)
inside the loop?
For example, if I write this:
X = [2 3 5];
Y = X + 2
Y =
4 5 7
do you see that it adds 2 to every element of X? However, if I write this:
X(1) = X(1) + 2
X =
4 3 5
then it impacts only one element of X.
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