How to use regexprep to modify strings while keeping constituent numbers intact?

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Aryan Ritwajeet Jha
评论： Voss 2022-6-10
Ran in:
I have a cell array of strings:
str = {'$d(V_1)$', ...
'$d(V_2)$', ...
'$d(V_3)$'}
str = 1×3 cell array
{'$d(V_1)$'} {'$d(V_2)$'} {'$d(V_3)$'}
I wish to convert the cell array of strings into:
strDesired = {'$function(a_{d(V_1)})$', ...
'$function(a_{d(V_2)})$', ...
'$function(a_{d(V_3)})$'}
strDesired = 1×3 cell array
{'$function(a_{d(V_1)})$'} {'$function(a_{d(V_2)})$'} {'$function(a_{d(V_3)})$'}
I tried using regexprep but I do not know how to extract and put in the same number in the new string strNew as the original str. Here I'm replacing the number with x just to demonstrate my incomplete solution:
patternToFind = 'd\(V_[1-9]\)';
patternToReplaceWith = 'function\(a_\{d\(V_x\)\}\)';
strNew = regexprep(str, patternToFind, patternToReplaceWith)
strNew = 1×3 cell array
{'$function(a_{d(V_x)})$'} {'$function(a_{d(V_x)})$'} {'$function(a_{d(V_x)})$'}
Could someone assist me in forming a patternToReplaceWith which will help me arrive at strDesired after performing the regexprep?

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采纳的回答

Voss
Voss 2022-6-10
编辑：Voss 2022-6-10
Ran in:
You can capture the V_1, V_2, etc., in tokens, then place those tokens in the output of regexprep by specifying $1 in patternToReplaceWith
str = {'$d(V_1)$', ...
'$d(V_2)$', ...
'$d(V_3)$'};
patternToFind = 'd\((V_[1-9])\)';
% ^ ^ I added parentheses here to capture tokens of the form V_[1-9]
patternToReplaceWith = 'function\(a_\{d\($1\)\}\)';
% ^^ tell regexprep to use token #1 (the only token) #1
strNew = regexprep(str, patternToFind, patternToReplaceWith)
strNew = 1×3 cell array
{'$function(a_{d(V_1)})$'} {'$function(a_{d(V_2)})$'} {'$function(a_{d(V_3)})$'}
Reference: https://www.mathworks.com/help/matlab/matlab_prog/tokens-in-regular-expressions.html
  2 个评论
Aryan Ritwajeet Jha
Aryan Ritwajeet Jha 2022-6-10
Thank you @Voss. Those parantheses are helpful for understanding exactly what token is extracted. I too was writing my (inefficient) solution not knowing that another user had already answered it in the meantime :D

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更多回答（1 个）

Aryan Ritwajeet Jha
Ran in:
Note: I'm answering my own question after seeing an apparent solution to my problem on MATLAB's help topic on Replace text using regular expression - MATLAB regexrep under the subheading Include Tokens in Replacement Text. I'll however wait for somene else to answer before possibly accepting this answer as I'm pretty sure there are more efficient ways to do the task.
str = {'$d(V_1)$', ...
'$d(V_2)$', ...
'$d(V_3)$'}
str = 1×3 cell array
{'$d(V_1)$'} {'$d(V_2)$'} {'$d(V_3)$'}
patternToFind = 'd\(V_(\w)\)';
Here \w looks for one word after V_ , which in the case of str is a number.
patternToReplaceWith = 'function\(a_\{d\(V_$1\)\}\)';
Here the $1 token extracts the first 'word' which was located by \w and inserts it into the replaced strings.
strNew = regexprep(str, patternToFind, patternToReplaceWith)
strNew = 1×3 cell array
{'$function(a_{d(V_1)})$'} {'$function(a_{d(V_2)})$'} {'$function(a_{d(V_3)})$'}

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