Getting the ratio of consecutive links in network using loop.

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Niraj Bal Tamang
Niraj Bal Tamang 2022-6-12
编辑： Voss 2022-6-12
I have two variables
A: 1 2 3 4 5 6 7 8 9
B: 2 10 5 8 12 6 14 6 2
I want to get the ratio of Bn/Bn-1 such that for A=1 is ratio is none, A=2 is B2/B1, A=3 is B3/B2 and so on.
Can anyone tell me how to do this in loop?
Thank you

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Voss
Voss 2022-6-12
Ran in:
A = 1:9; % unused
B = [2 10 5 8 12 6 14 6 2];
B_ratio = [NaN B(2:end)./B(1:end-1)] % no loop necessary
B_ratio = 1×9
NaN 5.0000 0.5000 1.6000 1.5000 0.5000 2.3333 0.4286 0.3333
  2 个评论
Niraj Bal Tamang
Niraj Bal Tamang 2022-6-12
Thank you so much. It gave "Dimensions of arrays being concatenated are not consistent." error first. then, I added semi colon after NaN and it fixed the error.
Voss
Voss 2022-6-12
编辑：Voss 2022-6-12
That means your B is a column vector (mine was a row vector). In any case, glad you got it working!

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