Getting the ratio of consecutive links in network using loop.

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Niraj Bal Tamang 2022-6-12

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1738710-getting-the-ratio-of-consecutive-links-in-network-using-loop

编辑： Voss 2022-6-12

采纳的回答： Voss

I have two variables

A: 1 2 3 4 5 6 7 8 9

B: 2 10 5 8 12 6 14 6 2

I want to get the ratio of Bn/Bn-1 such that for A=1 is ratio is none, A=2 is B2/B1, A=3 is B3/B2 and so on.

Can anyone tell me how to do this in loop?

Thank you

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Answer 1

Voss 2022-6-12

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1738710-getting-the-ratio-of-consecutive-links-in-network-using-loop#answer_984160

在 MATLAB Online 中打开

A = 1:9; % unused
B = [2 10 5 8 12 6 14 6 2];
B_ratio = [NaN B(2:end)./B(1:end-1)] % no loop necessary
B_ratio = 1×9
       NaN    5.0000    0.5000    1.6000    1.5000    0.5000    2.3333    0.4286    0.3333

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Niraj Bal Tamang 2022-6-12

Thank you so much. It gave "Dimensions of arrays being concatenated are not consistent." error first. then, I added semi colon after NaN and it fixed the error.