Symbolic integration vs numerical integration
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I have an expression with three variables x,y and v. I want to symbolically integrate v, and so I use int function
The command that I use is the following:
v =int((1-fxyz)*pv, v, y,+inf)% Its is taking too long for it to compute symbolically what do I do
Are there tricks to make int compute faster?
PS I havent given you what the function fxyv is but it is very complicated.
I know one option for me is to integrate numerically using for example integrate, however I want to note that the second part of this problem requires me to integrate g(x,y) over x and y from 0 to infinity. So I can't take numerical values of x and y when I want to integrate over v I think or maybe not ?
Thanks
2 个评论
Star Strider
2015-2-1
‘I haven’t given you what the function f(x,y,v) is but it is very complicated.’
It may not have an analytic solution. Consider using the integral function to integrate it numerically.
DM
2015-2-1
采纳的回答
Mike Hosea
2015-2-1
编辑：Mike Hosea
2015-2-1
It's likely to be quite slow, but it may be possible to take this on numerically. For performance reasons MATLAB insists that integrands be "vectorized", i.e. capable of accepting arrays of inputs and returning arrays of outputs, so we will need to address this. First let me assume that f and p are not coded in a way that would permit me to pass in an array and expect them to return an array of the same size.
gscalar = @(x,y)integral(@(v)arrayfun(@(v)(1 - f(x,y,v)).*p(v),v),y,inf);
g = @(x,y)arrayfun(gscalar,x,y);
T = integral2(@(x,y)exp(g(x,y)),0,inf,@(x)x,inf)
First we defined a gscalar function that accepts scalar x and y and evaluates the innermost integral. Then we used arrayfun to "vectorize" the gscalar function, creating a function that could accept arrays of x and y values and calculates the integrals element-wise. Finally integral2 calculates the outer double integral.
You can tack on 'AbsTol' and 'RelTol' arguments to the integral and integral2 calls.
In case you (or someone reading this) are not familiary with arrayfun, arrayfun is a "loop in a box" sort of thing. Think of
z = arrayfun(f,x,y)
as if it were
z = zeros(size(x));
for k = 1:numel(z)
z(k) = f(x(k),y(k));
end
but arrayfun should be faster than writing the loop in MATLAB.
You might be able to drop the use of arrayfun in the definition of gscalar if f and p are coded in such a way that they can handle an array of v inputs combined with scalar x and y inputs and deliver the correct value.
6 个评论
Mike Hosea
2015-2-2
Double-check that you've entered it in exactly as I typed it. I don't see any instances of @() anywhere in what I wrote, and it works for me, syntactically.
Having said that, I now realize that you have big problems numerically. In order for the double integral to converge, you need g(x,y) --> -inf as max(x,y)-->inf, but this means that the output of the first integral call must approach -inf. I doubt you can maintain any numerical precision with such a construction. Perhaps the problem can be reformulated via some transformations so that the integrals remain bounded.
Mike Hosea
2015-2-3
编辑：Mike Hosea
2015-2-4
You can't use syms here at all, or if you do, you need to use matlabfunction(f) and matlabfunction(v). Just define the functions directly in MATLAB like so:
p = @(v)v.^(2/3 - 1)
f = @(x,y,v)x.^2.*y.*v
Now these functions were easy to vectorize using the .^ and .* operators, so we don't need the arrayfun on the inside of the first integral call. I ran this:
p = @(v)v.^(2/3 - 1);
f = @(x,y,v)x.^2.*y.*v;
gscalar = @(x,y)integral(@(v)(1 - f(x,y,v)).*p(v),y,inf);
g = @(x,y)arrayfun(gscalar,x,y);
warning('off','MATLAB:integral:MinStepSize');
T = integral2(@(x,y)exp(g(x,y)),0,inf,@(x)x,inf)
and it gave me
T =
0
This appears to occur because the g(x,y) values are negative and grow so large in magnitude so quickly that exp(g(x,y)) is numerically zero at every sampled point.
Notice that I turned off a warning. If you don't, you'll see why. I didn't know it was possible to get this warning over and over again, or if I did at one time, I forgot about it. :)
DM
2015-2-4
更多回答（1 个）
Susan
2019-2-14
0 个投票
Dear Mike,
Could you please help me with this integral? TIA!!!!
a = 0 :10 and x = sqrt(2*a) and the goal is plotting Pb versus x(expresses in decibels (dB)).
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