How to resolve : increase max function value in fitting using fminsearch?

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Hi
I was trying to fit my data with fminsearch function with following code:
f = @(a,b,c,x) a - b.*(x).^c;
obj_fun = @(params) norm(f(params(1), params(2), params(3), x) -y);
sol = fminsearch(obj_fun, [1,1,1]);
err = .02*ones(size(x));
errorbar(x,y,err,'horizontal','s',"MarkerFaceColor",[0.8500, 0.3250, 0.0980], ...
"MarkerSize",4,"CapSize",4,"Color",[0.8500, 0.3250, 0.0980],"LineWidth",1)
hold on
x = linspace(min,max,20);
plot(x,f(sol(1),sol(2),sol(3),x),'-',"Color",[0.8500, 0.3250, 0.0980],"LineWidth",1)
hold off
Its getting the fit, but I think this is not best optimum fit its showing following message:
Exiting: Maximum number of function evaluations has been exceeded
- increase MaxFunEvals option.
Current function value: 2.586758
it will be realy great if some experties help me here to take care of this. Im attaching data here (data.txt).
Is there any other function which I can use instade of this to fit and better gobal optimazation.
Thank you in advance!

采纳的回答

Matt J
Matt J 2022-6-16
编辑:Matt J 2022-6-16
You could do as the message says and increas MaxFunEvals, but for your model, it would be better to download fminspleas,
[x,y]=readvars('https://www.mathworks.com/matlabcentral/answers/uploaded_files/1034515/data.txt');
funlist={1,@(c,xd) -xd(:).^c};
[c,ab]=fminspleas(funlist, 1 ,x, y);
sol=[ab(:).',c]
sol = 1×3
-6.5546 -0.0000 -6.0133
  2 个评论
Somnath Kale
Somnath Kale 2022-6-17
@Matt J thank you for your response!
Can you little bit elaborate the code, means fminsplease function and how your calculation that will be god to understand me as well!
Matt J
Matt J 2022-6-17
编辑:Matt J 2022-6-18
Fminspleas uses a technique which only needs to iterate over the c parameter, so it is an easier search.

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更多回答(1 个)

Matt J
Matt J 2022-6-16
编辑:Matt J 2022-6-16
If you have the Curve Fitting Toolbox,
[x,y]=readvars('https://www.mathworks.com/matlabcentral/answers/uploaded_files/1034515/data.txt');
ft=fit(x(:),y(:),'power2')
ft =
General model Power2: ft(x) = a*x^b+c Coefficients (with 95% confidence bounds): a = 1.124e-06 (-2.414e-05, 2.639e-05) b = -6.015 (-14.64, 2.609) c = -6.554 (-9.987, -3.121)
plot(ft,x,y)
  5 个评论
Matt J
Matt J 2022-6-17
@Sonnath what is unacceptable about the fit that your current model gives you? You'll notice that both fit() and fminspleas() are in agreement on the fitted parameters.
Somnath Kale
Somnath Kale 2022-6-17
@Matt J Im more intrested in fitting coefficint than that the good visual fit. I tried with fminplease it doing the job!
Thanks! looking forword to your help in future as well!

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