how to solve this
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Area A= pi*r^2 where r=pi^1/3-1
回答（2 个）
The Area A computed by MATLAB is as correct as the radius r given by you.
r = pi^1/3-1
A = pi*r^2
r = pi^1/3-1 % == (pi^1)/3 - 1 == pi/3 - 1
A = pi*r^2
r = pi^(1/3)-1 % pi to the one-third power, minus one
A = pi*r^2
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