I want to use a for loop inside a function, where the for loop contains a subfuction. Each loop must store the variable value and make a matrix of all values, but I get 0s :(

5 次查看（过去 30 天）
Nikolas Katsantonis
评论： Nikolas Katsantonis 2022-6-18
function [a] = Main(Coordinates)
a=5;
for n=1:a
Coordinates=3+n;
a= test(n,Coordinates)
end
end
function [A, B]= test(n,Coordinates)
A(n)= Coordinates*3;
B(n)= A(n)*Coordinates*6;
end
  3 个评论
显示 1更早的评论
Geoff Hayes
Geoff Hayes 2022-6-17
That makes sense, right? Look at this code
function [A, B]= test(n,Coordinates)
A(n)= Coordinates*3;
B(n)= A(n)*Coordinates*6;
end
You are creating a new A and B whenever the test function is called. These new variables/arrays won't have the history from previous calls to this function. So you are always returning arrays of zeros except for the nth value which is set in this function call.

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Geoff Hayes
Geoff Hayes 2022-6-17
@Nikolas Katsantonis - you are using a as an integer and as a result from test
a=5;
for n=1:a %<--- a as integer
Coordinates=3+n;
a= test(n,Coordinates) %<--- a as result
end
test should be returning two values and not arrays (you will need to correct this code), and so you would do something like
a=5;
for n=1:a
Coordinates=3+n;
[aValue, bValue] = test(n,Coordinates);
end
then store aValue into an array so that you don't overwrite it on each iteration of the loop
a=5;
myData = zeros(a,1);
for n=1:a
Coordinates=3+n;
[aValue, bValue] = test(n,Coordinates);
myData(n) = aValue;
end
then return myData in the signature of your function (not a).
  4 个评论
显示 2更早的评论
Geoff Hayes
Geoff Hayes 2022-6-17
You could try changing this code to
function [A, B]= test(n,Coordinates)
A = Coordinates*3;
B = A*Coordinates*6;
end
though the n can be removed since it is no longer relevant. It isn't clear to me why b isn't being set...it does for me when I try it.
A couple more things from
function [myData1,aValue,bValue,n] = Untitleddd(Coordinates)
a=5;
myData1 = zeros(a,1);% Added
for n=1:a
Coordinates=3+n;
[aValue, bValue] = test(n,Coordinates);
myData1(n)= aValue(n);%Added
end
end
Coordinates is passed in as an input parameter but is reset with 3+n. Is this intentional? Also, since test doesn't return arrays, then just do
myData1(n)= aValue;

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Characters and Strings 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by