Finding the maximum two values within one field conditioned on the values in another field

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Kristin 2022-6-20

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1744105-finding-the-maximum-two-values-within-one-field-conditioned-on-the-values-in-another-field

评论： Voss 2022-6-20

Hi,

I have a structure with 8 rows and 11 fields. The data contained in the 8 rows (corresponding to summary data of 8 blocks) belongs to different conditions of an experiment (rows 1,2,5,6 belong to condition A and rows 3,4,7,8 belong to condition B). I would like to extract the index (from 1 to 8) of the two maximum values within each condition.

I am currently struggeling with writing a code that extracts the maximum values only from the rows of the relevant condition and at the same time returns the number of the block/row that it refers to.

So I would, for example, like to get the maximum values of condition B, which are in my case in row/block 4 and 7. How do I do this?

Would be so grateful for an answer!!!

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Jan 2022-6-20

A short example with typical data would be useful.

Kristin 2022-6-20

编辑：Kristin 2022-6-20

在 MATLAB Online 中打开

%separately safe gains from Condition A and Condition B
condA_data = [feedback(1:2).gains feedback(5:6).gains];
condB_data = [feedback(3:4).gains feedback(7:8).gains];
gains_total = [feedback(1:8).gains];
%sort gains from Condition A and Condition B choice blocks in descending order
sorted_condA = sort(condA_data, 'descend');
sorted_condB = sort(condB_data,'descend');
%gain in best Condition A and Condition B blocks
top2_gains_condA = sorted_condAgains(1:2);
top2_gains_condB = sorted_condBgains(1:2);
%find the index of the two best Condition A and Condition B blocks
top2_condA_blocks = [(find(gains_total == top2_gains_condA(1))) (find(gains_total == top2_gains_condA(2)))];
top2_condB_blocks =[(find(gains_total == top2_gains_condB(1))) (find(gains_total == top2_gains_condB(2)))];

All variables are saved in the structure "feedback" and I would like to access the values of the field "gains" separately for condition A (condA) and condition B (condB).

To extract the maximum two values (maximal gains) of both conditions, I sorted the data from the field gains subsequently and saved the maximum two values in a variable called top2_gains_condA and top2_gains_condB, respectively.

Where things become problematic is the last two lines of code. What I have done so far is to create new variables and if I try to have the index of the maximum values returned, I would have indices from 1-4 for both variables. However, I would like to refer to the original indices, as saved in the field feedback.gains. This is what I tried to implement by looking for the values of the top2_gains variables in the list of the total gains (gains_total). As the gains in condA and condB sometimes overlap, however, this does not work.

In my feedback structure, I have a second field in which the blocknumber from 1-8 over row 1-8 are specified. Is there maybe an option to refer only to the values of the respective condition (A or B) by specifying the row/block by the blocknumber?

I hope my case became a bit clearer now. If you need more specification, please let me know.

Thank you already and Best regards :)

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Answer 1

Voss 2022-6-20

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1744105-finding-the-maximum-two-values-within-one-field-conditioned-on-the-values-in-another-field#answer_989570

在 MATLAB Online 中打开

% random data
feedback = struct('gains',num2cell(rand(1,8)));
disp([feedback.gains]);
    0.4040    0.2714    0.5874    0.8261    0.7476    0.6085    0.9514    0.5072
%separately save gains from Condition A and Condition B
idxA = [1 2 5 6];
idxB = [3 4 7 8];
gains_total = [feedback.gains];
condA_data = gains_total(idxA);
condB_data = gains_total(idxB);
%sort gains from free and forced choice blocks in descending order
[sorted_condA,sorted_idxA] = sort(condA_data,'descend');
[sorted_condB,sorted_idxB] = sort(condB_data,'descend');
%find the index of the two best free and forced choice blocks
top2_condA_blocks = idxA(sorted_idxA([1 2]))
top2_condA_blocks = 1×2
     5     6
top2_condB_blocks = idxB(sorted_idxB([1 2]))
top2_condB_blocks = 1×2
     7     4