Workaround for the expinv function in statistics toolbox
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Hi,
I have been working with the norminv function for a while using my own code as follow:
function z = norminv(p,sigma,mu)
z = sigma.*(-sqrt(2)*erfcinv(2*p))+mu;
end
However, I would like now to use the expinv function but I don't have access to the statistics toolbox. I was wondering if there is a way to work around using that particular function ?
Thanks !
采纳的回答
p = 0.3;
mu = 1/4;
x = -mu.*log(1-p)
x2 = expinv(p,mu)
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