Symbolic rewritten in matlab

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Miraboreasu
Miraboreasu 2022-6-21
评论： Walter Roberson 2022-6-21
alpha=log(r)/t0/(r-1);
beta=r*log(r)/t0/(r-1);
p0=p*(exp(-alpha*t)-exp(-beta*t))/(exp(-alpha*t0)-exp(-beta*t0));
%r=?
%I tried this, plug alpha and beta with the expressions
syms r t p p0 t0
alpha=log(r)/t0/(r-1);
beta=r*log(r)/t0/(r-1);
%p0=p*(exp(-(log(r)/t0/(r-1))*t)-exp(-(r*log(r)/t0/(r-1))*t))/(exp(-(log(r)/t0/(r-1))*t0)-exp(-(r*log(r)/t0/(r-1))*t0));
eqn=(p*(exp(-(log(r)/t0/(r-1))*t)-exp(-(r*log(r)/t0/(r-1))*t))/(exp(-(log(r)/t0/(r-1))*t0)-exp(-(r*log(r)/t0/(r-1))*t0))==p0);
r=solve(eqn,[t, p, p0 t0])
%It doesn't give what I want
Hello, I have a equation, p0= above
I want to rewrite it as r=something
how can I do this in MATLAB or any other website?
  1 个评论
Walter Roberson
Walter Roberson 2022-6-21
You cannot solve one equation for four variables. You should be trying
solve(eqn, r)

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采纳的回答

Star Strider
Star Strider 2022-6-21
Ran in:
An analytic solution is likely not possible, due to the nature of the expression.
The only option is to solve it numerically for ‘r’ given appropriate values for the other variables —
syms p p0 r t0 t
alpha=log(r)/t0/(r-1);
beta=r*log(r)/t0/(r-1);
Eqn = p0 == p*(exp(-alpha*t)-exp(-beta*t))/(exp(-alpha*t0)-exp(-beta*t0))
Eqn = 
p0fcn = matlabFunction(rhs(Eqn)-p0)
p0fcn = function_handle with value:
@(p,p0,r,t,t0)-p0-(p.*(exp(-(t.*log(r))./(t0.*(r-1.0)))-exp(-(r.*t.*log(r))./(t0.*(r-1.0)))))./(exp(-(r.*log(r))./(r-1.0))-exp(-log(r)./(r-1.0)))
p = rand;
p0 = rand;
t = rand;
t0 = rand;
r = fsolve(@(r)p0fcn(p,p0,r,t,t0), rand)
No solution found. fsolve stopped because the relative size of the current step is less than the value of the step size tolerance squared, but the vector of function values is not near zero as measured by the value of the function tolerance.
r = -0.0174
.

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