How to generate series by percentage difference using loop?

1 次查看(过去 30 天)
I have a value
A(1) = 60;
A(2) = A(1) *0.99;
A(3) = A(2) *0.99;
A(4) = A(3) *0.99;
A(5) = A(4) *0.99;
A(6) = A(5) *0.98; % Values changing after 5 iteration
.
.
.
A(11) = A(10) *0.97; % Values changing after 5 iteration
.
.
.
.till the differences reached to 0.01.
Please help me.

采纳的回答

KSSV
KSSV 2022-6-22
编辑:KSSV 2022-6-22
A = zeros([],1) ;
A(1) = 60 ;
dA = 1 ;
i = 1 ;
while dA > 0.01
i = i+1 ;
A(i) = A(i-1)*0.99 ;
dA = abs(A(i)-A(i-1)) ;
end
  4 个评论
Triveni
Triveni 2022-6-23
Value of .99 is not changing after 5th iteration. Means A(6) = A(5) *0.98; please correct.
Triveni
Triveni 2022-6-24
%----------------------------------------
PP = 28;
sdf = 0.995;
%----------------------------------------
%Generate Series
A = zeros([],1) ;
A(1) = PP;
dA = 1 ;
i = 1 ;
while dA > 0.0001
i = i+1 ;
if length(A)>4 && rem(length(A),5)==0
sdf = sdf-.01;
A(i) = A(i-1)*sdf ;
else
A(i) = A(i-1)*sdf ;
end
dA = abs(A(i)-A(i-1)) ;
end
A = round(unique(A'),2);
A = A(fliplr(1:end),:);
N = 0.05; % Round value
B = unique(nonzeros(round(A/N)*N));
A = B(fliplr(1:end),:);

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Loops and Conditional Statements 的更多信息

产品


版本

R2022a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by