what can we use when we dont have value in a matrix instead of 0?

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arian hoseini
arian hoseini 2022-6-25
评论： Cris LaPierre 2022-6-25
i have a matrix of my data and i dont want to put 0 for the items that i dont have ...is there any other way?
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arian hoseini
arian hoseini 2022-6-25
编辑：arian hoseini 2022-6-25
% relay awayBus closeBus Line Backup1 Backup2
Data= [1 1 2 1-6,1-3 14 nan
2 3 1 3-4 3 nan
3 4 3 4-5 4 nan
4 5 4 5-6 5 nan
5 6 5 6-1,6-2 7 6
6 2 6 2-1 1 nan
7 1 6 1-3,1-2 2 8
8 2 1 2-6 13 nan
9 1 3 1-6,1-2 14 8
10 3 4 3-1 9 nan
11 4 5 4-3 10 nan
12 5 6 5-4 11 nan
13 6 2 6-1,6-5 7 12
14 6 1 6-2,6-5 6 12];
Dimensions of matrices being concatenated are not consistent.
Error in ProtectionTask4_ArianHoseini (line 16)
Data= [1 1 2 1-6,1-3 14 NaN
i get this error is it because of 4th column

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Cris LaPierre
Cris LaPierre 2022-6-25
Ran in:
use nan?
data = rand(3);
data(2,3) = nan
data = 3×3
0.7049 0.8908 0.2471 0.2524 0.5020 NaN 0.4604 0.1822 0.3545
You could also use missing, especially if you are usure of the data type. The result is the same as nan for doubles.
data(3,2) = missing
data = 3×3
0.7049 0.8908 0.2471 0.2524 0.5020 NaN 0.4604 NaN 0.3545
c = ["a","b","c"];
c(1) = missing
c = 1×3 string array
<missing> "b" "c"
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arian hoseini
arian hoseini 2022-6-25
for example for relay 1 i need to sumZ(1)+min(Z2(14),Z2(2))....the indexes u see are from my Data
Cris LaPierre
Cris LaPierre 2022-6-25
Sorry, but I don't see how Z relates to Data.
Also, it appears your outer for loop in Zone 1 is unnecessary (for k = 1 : 2). It runs the same code without any changes. You'd get the same results without it.

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