unable to use solve or fsolve for linear system

2 次查看(过去 30 天)
syms R1 R2 R3 R4
COM = [-6,0,10]
r1 = [-54.2,-27.5,-16.4]
r2 = [-54.2,27.5,-16.4]
r3 = [42.9,-27.5,-16.4]
r4 = [42.9,27.5,-16.4]
rr1 = [0,0,R1]
rr2 = [0,0,R2]
rr3 = [0,0,R3]
rr4 = [0,0,R4]
mg = [0,0,980.65*16631]
eq(1) = cross(r1-r2,rr2) + cross(r1-r3,rr3) + cross(r1-COM,mg) + cross(r1-r4,rr4) == [0,0,0]
eq(2) = cross(r2-r1,rr1) + cross(r2-r3,rr3) + cross(r2-COM,mg) + cross(r2-r4,rr4) == [0,0,0]
eq(3) = cross(r3-r2,rr2) + cross(r3-r1,rr1) + cross(r3-COM,mg) + cross(r3-r4,rr4) == [0,0,0]
eq(4) = cross(r4-r2,rr2) + cross(r4-r3,rr3) + cross(r4-COM,mg) + cross(r4-r1,rr1) == [0,0,0]
j = fsolve(eq,[R1,R2,R3,R4])
im trying to solve the above system of linear equations for R1 R2 R3 & R4
the error is
Unable to perform assignment because the indices on the left side are not compatible with the size of the right side.
L_tilde2 = builtin('subsasgn',L_tilde,struct('type','()','subs',{varargin}),R_tilde);
C = privsubsasgn(L,R,inds{:});

采纳的回答

Torsten
Torsten 2022-6-26
编辑:Torsten 2022-6-26
Seems your equations are not independent.
syms R1 R2 R3 R4
COM = [-6,0,10];
r1 = [-54.2,-27.5,-16.4];
r2 = [-54.2,27.5,-16.4];
r3 = [42.9,-27.5,-16.4];
r4 = [42.9,27.5,-16.4];
rr1 = [0,0,R1];
rr2 = [0,0,R2];
rr3 = [0,0,R3];
rr4 = [0,0,R4];
mg = [0,0,980.65*16631];
%eq(1) = cross(r1-r2,rr2) + cross(r1-r3,rr3) + cross(r1-COM,mg) + cross(r1-r4,rr4) == [0,0,0]
%eq(2) = cross(r2-r1,rr1) + cross(r2-r3,rr3) + cross(r2-COM,mg) + cross(r2-r4,rr4) == [0,0,0]
%eq(3) = cross(r3-r2,rr2) + cross(r3-r1,rr1) + cross(r3-COM,mg) + cross(r3-r4,rr4) == [0,0,0]
%eq(4) = cross(r4-r2,rr2) + cross(r4-r3,rr3) + cross(r4-COM,mg) + cross(r4-r1,rr1) == [0,0,0]
%j = fsolve(eq,[R1,R2,R3,R4])
cross(r1-r2,rr2) + cross(r1-r3,rr3) + cross(r1-COM,mg) + cross(r1-r4,rr4)
ans = 
cross(r2-r1,rr1) + cross(r2-r3,rr3) + cross(r2-COM,mg) + cross(r2-r4,rr4)
ans = 
cross(r3-r2,rr2) + cross(r3-r1,rr1) + cross(r3-COM,mg) + cross(r3-r4,rr4)
ans = 
cross(r4-r2,rr2) + cross(r4-r3,rr3) + cross(r4-COM,mg) + cross(r4-r1,rr1)
ans = 
A = [0 -55 0 -55;55 0 55 0; 0 0 97.1 97.1;-97.1 -97.1 0 0];
rank(A)
ans = 3
b = [3588021833/8;-3588021833/8;-1648577405738025/2097152;836259700628521/1048576];
sol = A\b;
Warning: Matrix is close to singular or badly scaled. Results may be inaccurate. RCOND = 3.144153e-17.
R1 = sol(1)
R1 = -8.5635e+06
R2 = sol(2)
R2 = 3.5012e+05
R3 = sol(3)
R3 = 4.0891e+05
R4 = sol(4)
R4 = -8.5047e+06

更多回答(1 个)

Walter Roberson
Walter Roberson 2022-6-26
those cross() calls each return a vector, and you compare the vector to [0 0 0] giving a vector result. You then try to store the vector in a scalar location.
If you were to store the entire vector, then when you got to the fsolve you would have four sets of 3 equations, for a total of 12 equations. And you are trying to fsolve the 12 for four variables. That is unlikely to succeed.
  1 个评论
Dhanush Srikanth
Dhanush Srikanth 2022-6-26
Right, so should I store the result from each equation seperately and then pick any 4 equations and then use them in solve?

请先登录,再进行评论。

类别

Help CenterFile Exchange 中查找有关 Matrices and Arrays 的更多信息

产品


版本

R2021b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by