Finding the coordinates of a point given the gradient, distance and one set of coordinates

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Adil Saeed
Adil Saeed 2022-6-27
评论： Adil Saeed 2022-6-30
Hi im trying to find the coordinates of a point given the gradient (m), distance (s) and one set of coordinates (x1,y1). I have a simultaneous equation that needs solving but cannot seem to find the numerical answers i have calulated by hand in MATLAB.
m = y2-y1/x2-x1 and s = sqrt((x2-x1)^2 + (y2-y1)^2)
given that:
m = 0.4
x1 = 10
y1 = 4
s = 15
and solving to find x2 and y2.

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Torsten
Torsten 2022-6-27
编辑：Torsten 2022-6-27
Ran in:
m = 0.4;
x1 = 10;
y1 = 4;
s = 15;
z = [x1 y1] + s/sqrt(1+m^2)*[1 m];
x2 = z(1)
x2 = 23.9272
y2 = z(2)
y2 = 9.5709
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Torsten
Torsten 2022-6-30
Ran in:
v = 2; %harbor porpoises swim between 0.5 - 4.2 m/s
t = 5; %seconds
s = v*t; %metres
x0 = 0;
y0 = 0;
x1 = [1;2;3;4;5];
y1 = [6;7;8;9;10];
d = sqrt((x1-x0).^2+(y1-y0).^2); %Pythagoras Theorem for distance between the 2 (Source and Reciever) points
m = (y1-y0)./(x1-x0); %Gradient between the points
z1 = [x1,y1] + diag(s./sqrt(1+m.^2))*[ones(size(x1)),m]
z1 = 5×2
2.6440 15.8639 4.7472 16.6152 6.5112 17.3633 8.0614 18.1381 9.4721 18.9443
z2 = [x1,y1] - diag(s./sqrt(1+m.^2))*[ones(size(x1)),m]
z2 = 5×2
-0.6440 -3.8639 -0.7472 -2.6152 -0.5112 -1.3633 -0.0614 -0.1381 0.5279 1.0557

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