How to do the calculation of these three different size matrices ?

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Akash Pal
Akash Pal 2022-6-28
编辑： Amritesh 2022-6-28

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Amritesh
Amritesh 2022-6-28
编辑：Amritesh 2022-6-28
First we have to create and initialise the arrays
C = [100,150];
B = [1,1;0.923077,0.615385;1,1;1,1;1,1];
D1 = [0,1,1,0,0,1.923077,3389.76;0,0,1,0,1,2,1793;0,1,1,0,0,1.923077,3389.76;0,0,1,0,1,2,1793];
D2 = [1,1,0,0,0,1.615385,5538.952;1,1,0,0,0,1.615385,5538.952;1,0,0,1,0,2,3601;1,0,0,1,0,2,3601];
A(:,:,1) = D1;
A(:,:,2) = D2;
Now,
F2 in first row of second column of D1 will correspond to A(1,2,1). So,
F2 = B[F2,C1]*C[D1]/A[1,6,D1] will be equivalent to
A(1,2,1) = B(2,1)*C(1)/A(1,6,1)
Similarly, you can calculate for other cells.
Hope this solves your issue.
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Amritesh
Amritesh 2022-6-28
编辑：Amritesh 2022-6-28
Here, k = 1 signify D1 and k = 2 signify D2.
Just try dry run of loop using pen and paper.
You can accept the answer if you understood.

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