Function of a variable

2022 6 28
1 个回答
更新时间：2022 6 28
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0 个投票

The sc value in the equation B should be function of x
sc(x) that depends on range x= 0:0.01:10

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Garmit Pant
Garmit Pant 2022-6-28
Can you please elaborate as to what exactly is the problem that you are facing?
Anfal AlShehhi
Anfal AlShehhi 2022-6-28
I want to write the varibale sc in Equation B as a function of x
B(x) = rhoref/ rhot * x^2/ xref^2 * exp ( -2 * atm * xref)^10^-er/10 / T * sc(x)
x is the range from 0 to 10
Alan Stevens
Alan Stevens 2022-6-28
Then define
sc = @(x) ... % whatever the definition is.
But since you have set the values of x previously you could just set
sc = ... % directly in terms of x

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回答（1 个）

Alan Stevens
Alan Stevens 2022-6-28
编辑：Alan Stevens 2022-6-28

0 个投票

  1. You need to define sc before using it in B.
  2. In B you have ...1000/dref*dref.... This just means the dref va;lues cancel each other out. Did you mean ...1000/(dref*dref)...?
PS Upload the actual code, niot an image. Use the > symbol above.

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Anfal AlShehhi
Anfal AlShehhi 2022-6-28
Yes exactly. 1000/(dref*dref)
Anfal AlShehhi
Anfal AlShehhi 2022-6-28
编辑：Anfal AlShehhi 2022-6-28
clc; clear all;
% Defined values
atm=0.17 % km-1
xt=2.3; % target (x) in m
yt=2.3; % target (y) in m
p=50/100; % percent target
vis=23; %Visibility in km target
er=26; % LRF
dref=500; % LRF in m
pref=85/100; % LRF
vis2=23; % LRF Visbility
T=90/100; % LRF
% Range
x=0:0.01:10; % in km
A= exp(-2*atm.*x) % Attenuation func
sc =
B= ((pref/p)*((x.*x)*1000/dref*dref))*(((exp((-2*atm*dref/1000))*10^(-er/10)))/(T*sc)) % Sensi func
% plotting
figure
plot(A,x.*1000,'-b')
hold on
plot(B/1000,x.*1000,'-r')
grid on
xlabel("Range in km")
ylabel("Distance in km")
title("Range Preformance")
legend('Atmospheric Attenuation','Sensitivity')
hold off
Alan Stevens
Alan Stevens 2022-6-28
You need to define sc.
If you don't know what sc is, how is Matlab to know?

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