Index exceeds the number of array elements - Error message

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zen
zen 2022-6-28
评论： Voss 2022-6-30
So I am getting an error where I believe n1 is larger than the array after n becomes n = 3, which is giving the error in ma. Premise of the code is to take 1 2, 3 4 5, 6 7 8 9, etc. Pretty sure I have to change the length but not sure how to go about it. What should I do? Here is the code:
clear all
mdata = [1 2 3 4 5 6 7 8 9];
n1 = 1;
k = 1;
for n = 1:length(mdata)
ma(n) = (1/(k + 1)) * sum(mdata(n1:n1 + k));
n1 = ((n1 + k) + 1);
k = k + 1;
std_ma = std(mdata);
end
Error message:
Index exceeds the number of array elements (9).
Error in untitled22 (line 11)
ma(n) = (1/(k + 1)) * sum(mdata(n1:n1 + k));

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采纳的回答

Voss
Voss 2022-6-28
Ran in:
Here's one way to determine the number of iterations required:
clear all
mdata = [1 2 3 4 5 6 7 8 9];
n1 = 1;
k = 1;
N = numel(mdata);
n_iter = find(cumsum(2:N) <= N,1,'last')
n_iter = 3
for n = 1:n_iter
ma(n) = (1/(k + 1)) * sum(mdata(n1:n1 + k));
n1 = ((n1 + k) + 1);
k = k + 1;
std_ma = std(mdata);
end
disp(ma)
1.5000 4.0000 7.5000

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