How can I display all elements of an array in a single row?
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hi, if I have an array, how I can display all elements in single row if I did not know the length of that row(i did not know the no. of columns) . where the size of rows is not equal
for ex.
A=CGCKCCD?QDCQC??FE?N?NBCBNM?AEZE*GAAWE?E-GQE?R?N??Y
G?GRHTHYH?H*HMHDHPH?HLHWGMHH?Y?AHCGYGAHEGBG?E?HRG*
HKHFIMI*GKITHPI-LRH?GRH?IBGSL?I?IXIFLAIYIZISHLHQIK
GRH?HKIGGPHPIHIELELILHLRIDQWLDLCAWGGGDLQHQ?L
GLQ?FEN-LLKBGAE??-?BNDNMLTELK?KXK?NHEADX?ACBAWMGK?
G?EWGMHFHWGRIVHPHSIAHZGNGKHBS?GCCZE*K*GY?EHHGVN?ND
GRHQHMGNISBSEYLQFHBPIBIWBTCKN?VLC?AWKAR-?ZCZC?P?A*
IVEWSHF?P?KWSPYEBWGVHQHIBYG??QLYQHAWPEPN
GMHFG?HAH?IFEBIMSPVFMFR?A*VXSAQRPMN?CFA?YNB?C?TFYB
G?XFGKGRBWIKXMI?XPHKH*XSHMIDGNXKGDNDQ?XCN?N-HNXQZM
THANKS
4 个评论
Walter Roberson
2011-10-5
A(3,:)
However, it is not possible to have a numeric array that has rows of different lengths.
Depending on the data type and the needs of your program, you might be able to use some particular flag value to indicate the logical end of data in the row. For example if the flag value was 255, then you could use
t = A(3,:);
L = find(t == 255,1) - 1;
if isempty(L); L = length(t); end
t(1:L)
回答(3 个)
Walter Roberson
2011-10-5
I am not sure what you are asking, but the below seems like a plausible answer:
a1 = cellstr(A);
fprintf('%s ', a1{:}); fprintf('\n');
0 个评论
Dr. Seis
2011-10-5
If the string "A" also has end of line characters, then:
strf = strfind(A,sprintf('\n'));
B = {''};
if ~isempty(strf)
B = cellstr(A(1:strf(1)-1));
if numel(strf) > 1
for ii = 2 : numel(strf)
B(ii) = cellstr(A(strf(ii-1)+1:strf(ii)-1));
end
B(ii+1) = cellstr(A(strf(ii)+1:end));
else
B(2) = cellstr(A(strf(1)+1:end));
end
else
B = cellstr(A);
end
Where "B" is now a cell array. You can access/convert any row back to a string by, for example:
row_string = char(B(some_row));
3 个评论
Robert
2011-10-5
Arrays cannot have different numbers of columns in each row. Maybe you're dealing with a cell array, in which case you'd just type: A{3} For an array you'd type A(3,:).
3 个评论
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