Spit an array when the value 0 occurs until the value 2

I have an array time (6700x1) containing all numbers from -8 to 5 in ascending order.
I would like to have a new array (time_new) based on this that contains all value between 0 and 2.
I know that I can just open the array and look at which position the value 0 occurs and at wich index the value 2 and based on this do time(3981:4962). But since I'm dealing with several arrays where the position of these 2 numbers is not always the same I would like to have something more roboust that I can always use without every time open the array and look for the teo index.
Can someone help to with that?
Thanks in advance

1 个评论

Why do you think finding the position and using the index is not a robust method?
Use logical indexing then. (as @Voss has answered)

请先登录,再进行评论。

 采纳的回答

% an array time (6700x1) containing numbers from
% -8 to 5 in ascending order:
time = linspace(-8,5,6700).'
time = 6700×1
-8.0000 -7.9981 -7.9961 -7.9942 -7.9922 -7.9903 -7.9884 -7.9864 -7.9845 -7.9825
% time_new based on this that contains
% all value between 0 and 2:
time_new = time(time >= 0 & time <= 2) % use >, < if you want to exclude 0, 2
time_new = 1031×1
0.0010 0.0030 0.0049 0.0069 0.0088 0.0107 0.0127 0.0146 0.0166 0.0185

4 个评论

Thanks Voss, this was exactly what I was looking for ;)
What about if I would like to have an array based on this new one with exacty 102 elements equally spaced?
Like a linspace of the time_new vector
time = linspace(-8,5,6700).';
time_new = time(time >= 0 & time <= 2);
Like this?
time_new_new = linspace(time_new(1),time_new(end),102).'
time_new_new = 102×1
0.0010 0.0208 0.0406 0.0604 0.0802 0.1000 0.1198 0.1396 0.1594 0.1792

请先登录,再进行评论。

更多回答(1 个)

Your request is a bit ambiguous, so I will give two possibilities.
loc0 = find(YourArray == 0, 'first');
%use this
loc2F = find(YourArray == 2, 'first');
subsetF = YourArray(loc0:loc2F-1);
%OR use this
loc2L = find(YourArray == 2, 'last');
subsetL = YourArray(loc0:loc2L);
Now subsetF includes from the first 0 to the last value before the 2. subsetL includes from the first 0 to the last 2. You do not need both of these; I am just not clear which one you want.
Note that this code is not designed to work if there are no 0 or there are no 2.

3 个评论

Also,
look_for = 0:1; %or 0:2
subset = YourArray(ismember(YourArray, look_for));
This version looks for exact matches against what is in look_for, but does not depend upon the array being sorted and does not depend upon any particular value being present.
Thanks for the answer.
I have this error.
Error using find
Second argument must be a positive scalar integer.
loc0 = find(YourArray == 0, 1, 'first');
%use this
loc2F = find(YourArray == 2, 1, 'first');
subsetF = YourArray(loc0:loc2F-1);
%OR use this
loc2L = find(YourArray == 2, 1, 'last');
subsetL = YourArray(loc0:loc2L);

请先登录,再进行评论。

类别

帮助中心File Exchange 中查找有关 Matrix Indexing 的更多信息

产品

版本

R2022a

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by