Hello, I have a code which deals with symbolic variables and I have as output a vector whose dimension is known but variable.
The output is symbolic, for example a=[y_1/3+y_2/5 y_1/10+y_2/37]
I would like to save in an ASCII file, not binary, the output and for each row have one element of the vector. The tricky part is the saving in a file, I can do it only in bin, since when I type -ASCII it doesn't do it.
Here I attach a piece of code useful to understand. Thanks for your time.
Antonio
syms a b c x;
results=solve('a*x^2 + b*x + c');
save results.dat results
My output comes as:
results=[-(b + (b^2 - 4*a*c)^(1/2))/(2*a) -(b - (b^2 - 4*a*c)^(1/2))/(2*a)]

 采纳的回答

One may use DIARY( http://www.mathworks.com/help/releases/R2011b/techdoc/ref/diary.html ) to capture any output to the command window into a text file.
Otherwise, you may convert your symbolic variables into strings and write them into a text file, for instance:
syms a b c x;
results=solve('a*x^2 + b*x + c');
fid = fopen('myfile.txt', 'w');
fwrite(fid, char(results), 'char');
fclose(fid);
Hope this helps.
Abhi...

2 个评论

Dear Abhi, thanks a lot for your reply.
I wanted to isolate the single equations and the coefficients....I guess I need to work a bit on it, but what you wrote is useful.
Ciao
Thanks for the great answer, helped also me.
Nachum

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更多回答(2 个)

results = char(solve('a*x^2 + b*x + c'));

3 个评论

Hello Walter,
thanks for your answer, but this is not what I am looking for.
I want to save
%start code
>> syms a b c x;
>> results=solve('a*x^2 + b*x + c')
results =
-(b + (b^2 - 4*a*c)^(1/2))/(2*a)
-(b - (b^2 - 4*a*c)^(1/2))/(2*a)
save results.dat results
%end code
I want to save in a text file:
-(b + (b^2 - 4*a*c)^(1/2))/(2*a)
-(b - (b^2 - 4*a*c)^(1/2))/(2*a)
I don't know if it is possible.
Using your approach, it saves some numbers:
1.0900000e+002 9.7000000e+001 1.1600000e+002 1.1400000e+002 1.0500000e+002 1.2000000e+002 4.0000000e+001 9.1000000e+001 9.1000000e+001 4.5000000e+001 4.0000000e+001 9.8000000e+001 3.2000000e+001 4.3000000e+001 3.2000000e+001 4.0000000e+001 9.8000000e+001 9.4000000e+001 5.0000000e+001 3.2000000e+001 4.5000000e+001 3.2000000e+001 5.2000000e+001 4.2000000e+001 9.7000000e+001 4.2000000e+001 9.9000000e+001 4.1000000e+001 9.4000000e+001 4.0000000e+001 4.9000000e+001 4.7000000e+001 5.0000000e+001 4.1000000e+001 4.1000000e+001 4.7000000e+001 4.0000000e+001 5.0000000e+001 4.2000000e+001 9.7000000e+001 4.1000000e+001 9.3000000e+001 4.4000000e+001 3.2000000e+001 9.1000000e+001 4.5000000e+001 4.0000000e+001 9.8000000e+001 3.2000000e+001 4.5000000e+001 3.2000000e+001 4.0000000e+001 9.8000000e+001 9.4000000e+001 5.0000000e+001 3.2000000e+001 4.5000000e+001 3.2000000e+001 5.2000000e+001 4.2000000e+001 9.7000000e+001 4.2000000e+001 9.9000000e+001 4.1000000e+001 9.4000000e+001 4.0000000e+001 4.9000000e+001 4.7000000e+001 5.0000000e+001 4.1000000e+001 4.1000000e+001 4.7000000e+001 4.0000000e+001 5.0000000e+001 4.2000000e+001 9.7000000e+001 4.1000000e+001 9.3000000e+001 9.3000000e+001 4.1000000e+001
Thanks again for your reply
Antonio
This is not something I can test myself, but I can tell you that that output does not look as expected and documented.
I will try in a different way and see what it happens....
Thanks for your reply, Antonio

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To isolate each row you can write:
fid = fopen('myfile.txt', 'w');
for i=1:length(results)
fprintf(fid, '%s\n',char(results(i)));
end
fclose(fid);
Generally first you should convert each argument into string and then using string manipulation functions arrange them

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