I have matrix K and Z

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jane
jane 2022-7-1
评论： KALYAN ACHARJYA 2022-7-1
I have matrix K and Z
K = [[ 12, 50, 15, 99, 61, 74 ,71],
[54, 23, 14, 13, 16, 89,67],
[12, 45, 78, 90, 12, 56, 16]].
Z = [[ 0, 1, 0, 0, 0, 0.1],
[ 0, 0, 0, 0 , 0, 0, 0]],
[ 0, 0 , 1, 0 , 0, 0,0]],
How to make the value of the first row in the K matrix be 0 if the Z matrix contains the number 1.
for example in the first row in the Z matrix there is a value of 1, how do you make the values in the first row (12, 50, 15, 99, 61, 74 ,71) of the K matrix become ( 0, 0, 0, 0, 0, 0 , 0). Thanks

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回答（2 个）

David Hill
David Hill 2022-7-1
s=logical(sum(Z,2));
K(s,:)=0;
KALYAN ACHARJYA
KALYAN ACHARJYA 2022-7-1
编辑：KALYAN ACHARJYA 2022-7-1
Ran in:
Another way:
K = {[12, 50, 15, 99, 61, 74 ,71];[54, 23, 14, 13, 16, 89,67];[12, 45, 78, 90, 12, 56, 16]};
Z = {[ 0, 1, 0, 0, 0, 0.1];[ 0, 0, 0, 0 , 0, 0, 0];[ 0, 0 , 1, 0 , 0, 0,0]};
for i=1:length(Z)
if any( Z{i}==1)
dat=length(K{i});
K{i}= zeros(1,dat);
end
end
K
K = 3×1 cell array
{[ 0 0 0 0 0 0 0]} {[54 23 14 13 16 89 67]} {[ 0 0 0 0 0 0 0]}
  2 个评论
jane
jane 2022-7-1
sorry but this doesn't work.
the text in the command window looks like the following "brace indexing is not supported for this type of variable." for if any(z{i}==1)
KALYAN ACHARJYA
KALYAN ACHARJYA 2022-7-1
It's working in Live Matlab, see the results too.

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