How to implement the output matrix without if conditions

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Shuoze Xu
Shuoze Xu 2022-7-2
评论： KSSV 2022-7-2
Hi.
This is a review problem that requires the use of nested loops to output the following matrix.
1
2 3
3 4 5
4 5 6 7
5 6 7 8 9
Here is my code, i use the complex if statement to output.
matrix = []; % create empty matrx
nums = 0; % set a variable named nums and euqal to zero
nums_three = 3;
nums_four = 4;
nums_five = 5;
% use nested loop
for i = 1:5
for j = 1:i % the nums of columns will increase with the end of one outer loop
nums = nums + 1;
matrix(i,j) = nums;
if (i == 3)
matrix(i,j) = nums_three;
nums_three = nums_three+1;
elseif (i == 4)
matrix(i,j) = nums_four;
nums_four = nums_four+1;
elseif(i == 5)
matrix(i,j) = nums_five;
nums_five = nums_five + 1;
end
end
end
disp(matrix);
Here is my output
1 0 0 0 0
2 3 0 0 0
3 4 5 0 0
4 5 6 7 0
5 6 7 8 9
The first question i want to ask is that how can i remove zero in this matrx?
The second question is that Is there another way to output the matrix without using if- statement?
Thank you all.

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采纳的回答

KSSV
KSSV 2022-7-2
编辑：KSSV 2022-7-2
n = 5 ;
A = zeros(n) ;
for i = 1:n
for j = 1:i
A(i,j) = i+j-1 ;
end
end
A
You cannot remove zeros, if you want it as a matrix. Other option is you can replace zeros with NaNs.

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