multiply a 1 by 500 matrix to a 688 by 550 matrix and want to get the result for iteration instead of final value from 1 by 500 matrix!

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Kai5er
Kai5er 2022-7-2
评论： Steven Lord 2022-7-3
for i = 1:5
r(:,:) = (ait(:,i)*podu);
end
ait is 1 by 500 matrix and podu is 688 by 550 matrix. Using this code gives me the result for the product of 5th value of ait times the podu matrix. I want to sum all the values for all the iteration and create a 688 by 550 matrix for r!
Thank you
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Steven Lord
Steven Lord 2022-7-3
@Kai5er flagged this as Unclear stating "I think the question is unclear and i want to remove it and will upload with better explanation"
You've already received an answer. Don't remove it and repost. Please post comments clarifying the question.

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采纳的回答

Voss
Voss 2022-7-2
It's not clear to me whether "all the iterations" means to iterate over the first 5 elements of ait or to iterate over all elements of ait, so the below has it both ways:
Method 1, similar to your loop:
% initialize r to be a matrix of zeros, the same size as podu
r = zeros(size(podu));
for i = 1:5 % first 5 only, or
% for i = 1:numel(ait) % all
r = r + ait(i)*podu;
end
Method 2:
% sum the ait first, then multiply the sum by podu:
r = sum(ait(1:5))*podu; % first 5 only, or
% r = sum(ait)*podu; % all

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