Integrating this function and trying to solve for a variable displays errors!

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adam puchalski
adam puchalski 2022-7-7
编辑： Torsten 2022-7-7
Here is the code with the error:
syms initial theta
ints = int(1/sqrt(cos(initial)-cos(theta)),initial,pi/2);
func = L/sqrt((E*I)/(2*F)) - ints;
S = fsolve(func,0);
S
Error using lsqfcnchk (line 108)
If FUN is a MATLAB object, it must have an feval method.
Error in fsolve (line 235)
funfcn = lsqfcnchk(FUN,'fsolve',length(varargin),funValCheck,gradflag);
Error in GuessesICs (line 65)
S = fsolve(func,0);
I am trying to solve for initial in this function. the fuction is in respect to theta (dθ) so that should not be a problem?
Anythign appreciated
Thank you

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采纳的回答

Torsten
Torsten 2022-7-7
编辑：Torsten 2022-7-7
Ran in:
L = 1;E = 1;I = 1;F=1;
func = @(initial) L/sqrt((E*I)/(2*F)) - integral(@(theta)1./sqrt(cos(initial)-cos(theta)),initial,pi/2);
S = fsolve(func,0.5)
Equation solved. fsolve completed because the vector of function values is near zero as measured by the value of the function tolerance, and the problem appears regular as measured by the gradient.
S = 1.1094
func(S)
ans = -8.5387e-12

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