How to return a true/false logical array from a string array of repeating numbers?

Liv
2022 7 7
2 个回答
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更新时间：2022 7 7
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ans = 3 2 1 5 1 4 0
I want this to return a 7x1 logical array 0 0 1 0 1 0 0. Corresponding to the repeating “1” in the ans variable. Or 1 1 0 1 0 1 1. Whichever is easier to program. How do I do this?

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Rohit Kulkarni
Rohit Kulkarni 2022-7-7
Ran in:

1 个投票

Ran in:
I think this may work:
A = [3 3 2 1 5 1 0 4];
[uniqueA i j] = unique(A,'first');
idRep = find(not(ismember(1:numel(A),i)))
idRep = 1×2
2 6
rep_var = A(idRep)
rep_var = 1×2
3 1
ll = ismember(A,rep_var)
ll = 1×8 logical array
1 1 0 1 0 1 0 0

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Jon
Jon 2022-7-7

0 个投票

x = [3 2 1 5 1 4 0]
L = x == 1

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Liv
Liv 2022-7-7
I should have specified that these numbers change depending on the output of other variables in my program. For example the ans variable could be “3 3 2 1 5 1 0 4” instead. Then I would want it to return “1 1 0 1 0 1 0 0”. I need a logical array that shows if there are repeats.
Jon
Jon 2022-7-7
Ran in:
Ran in:
Sorry I misunderstood what you were looking for. I think this does what you want:
x = [3 3 2 1 5 1 0 4]
x = 1×8
3 3 2 1 5 1 0 4
u = unique(x)
u = 1×6
0 1 2 3 4 5
[N,edges,bin]= histcounts(x,[u,u(end)+1])
N = 1×6
1 2 1 2 1 1
edges = 1×7
0 1 2 3 4 5 6
bin = 1×8
4 4 3 2 6 2 1 5
N(bin)>1
ans = 1×8 logical array
1 1 0 1 0 1 0 0
Liv
Liv 2022-7-7
No, I seem to be getting an array bounds error. I’m sure if I went through the troubleshooting process that it would work, but for now I will be using the other user’s answer. If I ever go back to it again then I will update this thread.
Jon
Jon 2022-7-7
编辑：Jon 2022-7-7
That's fine as long as you have a solution, but I'm puzzled, as to why you would have array bounds errors, when as you can see it ran without issues in the small example I show above. As you had an array bounds error, are you sure you used :
[N,edges,bin]= histcounts(x,[u,u(end)+1])
and not:
[N,edges,bin]= histcounts(x,[u,u(end+1)])

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