How to create structs with text data

Question

fernando aguirre 2022-7-7

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1755500-how-to-create-structs-with-text-data

评论： Rik 2024-10-21

exampledata.txt

I am struggling to find a way to separate the cells I created from the data I read in into an ordered structured based on the parent string

i.e. want data = {"couple1:" , " child1:" , " grandchild1: 3",....}

into couple1.child1.grandchild1 = 3

I thought of using isspace to determine if the cell has spaces or not and sum from there to check the previous cell, but it sounds memory expensive if my text files is much bigger.

Thanks!

fid = open('exampledata.txt')
Error using open
Failed to open MATLAB Editor.
tline = fgetl(fid);
data = cell(0,1);
while ischar(tline)
    data{end+1,1} = tline;
    tline = fgetl(fid);
end
fclose(fid);

1 个评论
显示 -1更早的评论隐藏 -1更早的评论

Rik 2022-7-7

Why do you want that structure? It seems very difficult to work with the data once it is inside that data structure.

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Mathieu NOE 2022-7-8

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1755500-how-to-create-structs-with-text-data#answer_1002910

在 MATLAB Online 中打开

hello

check my demo code below :

clc
clearvars
mylines = readlines('exampledata.txt'); %
[m,n] = size(mylines);
% grouping all variables under an overarching struct
 S = struct() ;
 
 for ck = 1 : m
     tmp = char(mylines(ck));
     
     % empty default numeric values
     lev1_num = [];
     lev2_num = [];
     lev3_num = [];
     
     if length(tmp)>0
         nb_of_leading_spaces = max(find(isspace(tmp(1:min(length(tmp),9))))); % assuming here no more than 9 leading spaces are used (adjust)
        
         %% level 1 (couple)
         if isempty(nb_of_leading_spaces) % check no space characters in the 3 first positions
             ind = strfind(tmp,':');
             lev1 = tmp(1:ind-1)
             S.(lev1) = lev1_num;
         end
         
         %% level 2 (child)
         if nb_of_leading_spaces == 3 % check no space characters in the 3 first positions
             ind = strfind(tmp,':');
             lev2 = tmp(1:ind-1);
             lev2 = strtrim(lev2); % remove leading spaces
             % check if data after ':' is numeric
             lev2_num = tmp(ind+1:end);
             if ~isempty(lev2_num)
                 lev2_num = str2num(lev2_num)
             end
             S.(lev1).(lev2) = lev2_num;
         end
         
         %% level 3 (grandchild)
         if nb_of_leading_spaces == 6 % check no space characters in the 3 first positions
             ind = strfind(tmp,':');
             lev3 = tmp(1:ind-1)
             lev3 = strtrim(lev3); % remove leading spaces
           % check if data after ':' is numeric
             lev3_num = tmp(ind+1:end);
             if ~isempty(lev3_num)
                 lev3_num = str2num(lev3_num)
             end
             S.(lev1).(lev2).(lev3) = lev3_num;
         end         
         
     end
    
 end

2 个评论
显示无隐藏无

Rik 2022-7-8

You can probably make the depth dynamic by using the setfield function.

Rik 2024-10-21

Deleting your answer and reposting as comment is not what I meant. Go to https://www.mathworks.com/matlabcentral/discussions and see which category fits best.

Although, to be honest, I don't understand why you don't put this in a Word document on your own computer. What is the actual benefit to others of this wall of text?

请先登录，再进行评论。

How to create structs with text data

1 个评论
显示 -1更早的评论隐藏 -1更早的评论

回答（1 个）

2 个评论
显示无隐藏无

另请参阅

类别

标签

产品

版本

Community Treasure Hunt

How to create structs with text data

1 个评论 显示 -1更早的评论隐藏 -1更早的评论

回答（1 个）

2 个评论 显示 无隐藏 无

另请参阅

类别

标签

产品

版本

Community Treasure Hunt

1 个评论
显示 -1更早的评论隐藏 -1更早的评论

2 个评论
显示无隐藏无