ezfit using a function
11 次查看(过去 30 天)
显示 更早的评论
I use ezfit to fit a gaussian in my data. It is straight forward as it is in the ezfit examples:
f1 = ezfit(x,counts,'gauss');
showfit(f1)
I want to fit my own function. So before doing that, I attempted using the equation of gaussian, exaclty the same equation in the ezfit documentation to fit the data ( http://www.fast.u-psud.fr/ezyfit/html/ezfit.html ). I am doing this to check if I am doing any mistakes. I did as follows
f1 = ezfit(x,counts,'a*exp(-(x-x0)^2/(2*s^2))');
showfit(f1)
This time it doesn't fit! Could you please tell me what is wrong in it?
2 个评论
Natalia Demidova
2022-7-12
Hi,
Notice in the ezfit documentation the way functions are specified are with syntax of "y=" as in a usual function. Thus it should look like:
f1 = ezfit(x,counts,'y = a*exp(-(x-x0)^2/(2*s^2))');
Further for your own function you can specify specific guesses for parameters (such as a and s here). The first guesses for the function (ex. a=1 and s=2) to try would be after semicolon in the same string and look like:
f1 = ezfit(x,counts,'y = a*exp(-(x-x0)^2/(2*s^2)); a=1; s=2');
Have fun :)
回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Statistics and Machine Learning Toolbox 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!