Mean of each Value in a Cell Array

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Hello,
I havea cell A (107x3), with each 14x8 double.
I want to create a cell A_mean 1x3 that just contain three 14x8 doubles, that are the mean of all the value.
I mean, A_mean{1,1}(1,1) should be the mean(A{1,1}(1,1),A{2,1}(1,1)...A{107,1}(1,1)), and the same for all the others numbers.
I really don't know how can I do it..
Thanks in advance :)

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Voss
Voss 2022-7-8
% a cell A (107x3), with each 14x8 double
A = arrayfun(@(~)randn(14,8),zeros(107,3),'UniformOutput',false)
A = 107×3 cell array
{14×8 double} {14×8 double} {14×8 double} {14×8 double} {14×8 double} {14×8 double} {14×8 double} {14×8 double} {14×8 double} {14×8 double} {14×8 double} {14×8 double} {14×8 double} {14×8 double} {14×8 double} {14×8 double} {14×8 double} {14×8 double} {14×8 double} {14×8 double} {14×8 double} {14×8 double} {14×8 double} {14×8 double} {14×8 double} {14×8 double} {14×8 double} {14×8 double} {14×8 double} {14×8 double} {14×8 double} {14×8 double} {14×8 double} {14×8 double} {14×8 double} {14×8 double} {14×8 double} {14×8 double} {14×8 double} {14×8 double} {14×8 double} {14×8 double} {14×8 double} {14×8 double} {14×8 double} {14×8 double} {14×8 double} {14×8 double}
% I want to create a cell A_mean 1x3 that just contain three
% 14x8 doubles, that are the mean of all the value
N = size(A,2);
A_mean = cell(1,N);
for ii = 1:N
A_mean{ii} = mean(cat(3,A{:,ii}),3);
end
disp(A_mean);
{14×8 double} {14×8 double} {14×8 double}
  4 个评论
Fabio Taccaliti
Fabio Taccaliti 2022-7-8
Ohh you are right!! Thanks a lot for the help!

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