Plot an equation in time span T=[0,t]

Question

Fatemeh Salar 2022-7-9

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1756415-plot-an-equation-in-time-span-t-0-t

编辑： Karim 2022-7-9

采纳的回答： Karim

在 MATLAB Online 中打开

Hi,

I am about to plot an equation but i have 4 variables (including t), how can I plot this equation in domain of 0-T ?

clc
clear
close all
a=input('Please enter a : ')
b=input('Please enter b : ')
c=input('Please enter c : ')
t=input('Please enter t : ')
if(a*b/c>1)
    for(0:t)
    y=(e^a)*sin(c*t)/sqrt(b);
    plot(t,y)
    end 
elseif(a*b/c<1 && a*b/c>0)
        y=sin(a)*sqrt(b*t)/sin(c);
        plot(t,y)
elseif(a*b/c<1)
        y=cos(a)*e^(b*t)/(c);
        plot(t,y)
        end

thanks

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Answer 1

Karim 2022-7-9

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1756415-plot-an-equation-in-time-span-t-0-t#answer_1003585

编辑：Karim 2022-7-9

在 MATLAB Online 中打开

You need to create a vector, below you can see a method using the "linspace" function. This creates a vector between 0 and t with 100 elements.

a = 3; % input('Please enter a : ')

b = 2; % input('Please enter b : ')

c = 7; % input('Please enter c : ')

t = 5; % input('Please enter t : ')

% create a vector T between [0 T] with 100 elements

t = linspace(0,t,100);

check = a*b/c;

if check > 1

y = (e^a)*sin(c.*t)./sqrt(b);

elseif check <= 1 && check >= 0

y = sin(a)*sqrt(b.*t)./sin(c);

else % i.e. check < 1

y = cos(a)*e.^(b.*t)./c;

end

figure

plot(t,y)

xlabel('t axis')

ylabel('y values')

grid on

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Torsten 2022-7-9

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You mean

if (a*b/c>1)
    y = (e^a)*sin(c.*t)./sqrt(b);
elseif (a*b/c<=1 && a*b/c>=0)
    y = sin(a)*sqrt(b.*t)./sin(c);    
elseif (a*b/c<0)
    y = cos(a)*e.^(b.*t)./c;
end

instead of

if (a*b/c>1)
    y = (e^a)*sin(c.*t)./sqrt(b);
elseif (a*b/c<1 && a*b/c>0)
    y = sin(a)*sqrt(b.*t)./sin(c);    
elseif (a*b/c<1)
    y = cos(a)*e.^(b.*t)./c;
end