add value from single element of array

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Jernej Primozic 2022-7-10

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回答： the cyclist 2022-7-10

Hi. I am writting a code where i would like to add value from array. So I have one value BAT which is a number. I have an array the size of 35040x1. How can I use for loop to add one value per one iteration to increase BAT value?

So below I managed to calculate a value for bat which is one value. but then after that I dont know what to use to still use this value and go through an array

for jj = 1:length(W_br)
    if jj == 1                                                                      
        max_kap=C*kap_bat;
        bat(jj,1)=0.5*max_kap(jj);
        bat(jj,1) = bat(jj,1) - W_br(jj)
    end
    if jj > 1 && jj < 5
        bat(jj) = bat(jj) - W_br(jj)
    end
end

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the cyclist 2022-7-10

I don't quite understand your question.

Could you give a small example of an input (maybe with a smaller vector that only has a few elements) and the output you expect?

Jernej Primozic 2022-7-10

Okey so i am calculating a value of battery (capcity) throuh time. I was provided with 2 elements (how much does my house use energy and how much does solar panels make)

So lets say

BAT = 7.6 consumption 3 production 5

for loop returns value: BAT = 9.7 (consumption - production)

so i have a whole array full of this 2 data but only a value for BAT

So what would I have to writte so the for loop would return actal value of BAT after going through this two arrays?

consumption: production:

0.08 0.07

0.08 0.00

0.16 0.58

0.00 0.06

BAT value after first loop is: BAT = 7.6-0.08+0.07 = 7.5

after that it should be 6.7 and so on

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Answer 1

the cyclist 2022-7-10

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在 MATLAB Online 中打开

Your example is confusing to me, partly because I think you made some careless math errors. But, the way I could approach this is to calculate the cumulative consumption and production, and then just use vector math (not a for loop) to get the BAT value at every step. Something like this:

consumption = [0.08 0.08 0.16 0.00];
production  = [0.07 0.00 0.58 0.06];
cumulativeConsumption = cumsum(consumption);
cumulativeProduction = cumsum(production);
BAT_initial = 7.6;
BAT = BAT_initial - cumulativeConsumption + cumulativeProduction
BAT = 1×4
    7.5900    7.5100    7.9300    7.9900