How to replace numbers in a matrix with another number?

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Omm Samantaray
Omm Samantaray 2022-7-13
评论： Voss 2024-10-29，17:33
I am stuck with a problem. I have a 2D matrix, let’s say, m*n as the size of the matrix. I want to put the values whose magnitude is less than a given constant (a very small decimal number) as 0, but I want to avoid for loop in my code for this.
Is there any way to do this?
Thank you.
  2 个评论
N/A
N/A 2024-10-29，17:31
移动：Voss 2024-10-29，17:32
0 0 0 0 0
d = 0 0 0 6 6
0 0 0 6 6
help me how to create this coding
Voss
Voss 2024-10-29，17:33
Ran in:
d = [0 0 0 0 0; 0 0 0 6 6; 0 0 0 6 6]
d = 3×5
0 0 0 0 0 0 0 0 6 6 0 0 0 6 6
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采纳的回答

Abhijit Nayak
Abhijit Nayak 2022-7-13
I guess from my understanding of your question that you just want to replace the values with 0 if their magnitude is less than a number.
Try the given below code. It is better than having for loop for this operation in MATLAB.
A=rand(6,5)
n=0.5;
A(abs(A)<n)=0

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