Creating a string with Permutation

Question

Chris Dan 2022-7-15

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1761025-creating-a-string-with-permutation

回答： Voss 2022-7-15

采纳的回答： Adam Danz

在 MATLAB Online 中打开

Hi,

I have a short question, I am creating a string with a loop but I cannot do the permutation/combination correctly

here is my code

Axes_name = {'sint0.2';'sint0.5';'sint0.7'};
fold_2 = {'BCA';'BPCA';'DLA';'DLCA'};
C_ext = nan*zeros(length(Axes_name),length(fold_2));
for i=1:length(Axes_name)
    for j=1:length(fold_2)
        
        leg{sub2ind(size(C_ext),i,j)} = [Axes_name{i} ' ' fold_2{j}];
    end
end

I am trying to make combinations like this:

sint0.2 BCA

sint0.2 BPCA

sint0.2 DLA

sint0.2 DLCA

sint0.5 BCA

sint0.5 BCPA

sint0.5 DLA

sint0.5 DLCA

...

and so on, but i am not getting it correctly.Does any know what changes i should do

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Adam Danz 2022-7-15

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1761025-creating-a-string-with-permutation#answer_1008315

编辑：Adam Danz 2022-7-15

在 MATLAB Online 中打开

I believe this is what you're working toward.

Axes_name = {'sint0.2';'sint0.5';'sint0.7'};
fold_2 = {'BCA';'BPCA';'DLA';'DLCA'};
str = compose('%s %s', string(Axes_name), string(fold_2)')
str = 3×4 cell array
    {'sint0.2 BCA'}    {'sint0.2 BPCA'}    {'sint0.2 DLA'}    {'sint0.2 DLCA'}
    {'sint0.5 BCA'}    {'sint0.5 BPCA'}    {'sint0.5 DLA'}    {'sint0.5 DLCA'}
    {'sint0.7 BCA'}    {'sint0.7 BPCA'}    {'sint0.7 DLA'}    {'sint0.7 DLCA'}

If you want a column vector,

str(:)
ans = 12×1 cell array
    {'sint0.2 BCA' }
    {'sint0.5 BCA' }
    {'sint0.7 BCA' }
    {'sint0.2 BPCA'}
    {'sint0.5 BPCA'}
    {'sint0.7 BPCA'}
    {'sint0.2 DLA' }
    {'sint0.5 DLA' }
    {'sint0.7 DLA' }
    {'sint0.2 DLCA'}
    {'sint0.5 DLCA'}
    {'sint0.7 DLCA'}

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

Answer 2

Paul 2022-7-15

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1761025-creating-a-string-with-permutation#answer_1008320

在 MATLAB Online 中打开

Hi hazmah,

Is this what you're looking for?

Axes_name = string({'sint0.2';'sint0.5';'sint0.7'})
Axes_name = 3×1 string array
    "sint0.2"
    "sint0.5"
    "sint0.7"
fold_2 = string({'BCA';'BPCA';'DLA';'DLCA'})
fold_2 = 4×1 string array
    "BCA"
    "BPCA"
    "DLA"
    "DLCA"
result = reshape(Axes_name.' + " " + fold_2,[],1)
result = 12×1 string array
    "sint0.2 BCA"
    "sint0.2 BPCA"
    "sint0.2 DLA"
    "sint0.2 DLCA"
    "sint0.5 BCA"
    "sint0.5 BPCA"
    "sint0.5 DLA"
    "sint0.5 DLCA"
    "sint0.7 BCA"
    "sint0.7 BPCA"
    "sint0.7 DLA"
    "sint0.7 DLCA"

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

Answer 3

Voss 2022-7-15

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1761025-creating-a-string-with-permutation#answer_1008335

在 MATLAB Online 中打开

Axes_name = {'sint0.2';'sint0.5';'sint0.7'};
fold_2 = {'BCA';'BPCA';'DLA';'DLCA'};

You can change the size of C_ext to be length(fold_2)-by-length(Axes_name), since you want to cycle through the fold_2 values first in leg. (Swap j and i where they're used in sub2ind as well.)

C_ext = nan*zeros(length(fold_2),length(Axes_name));
for i=1:length(Axes_name)
    for j=1:length(fold_2)
        leg{sub2ind(size(C_ext),j,i)} = [Axes_name{i} ' ' fold_2{j}];
    end
end
leg = leg.'
leg = 12×1 cell array
    {'sint0.2 BCA' }
    {'sint0.2 BPCA'}
    {'sint0.2 DLA' }
    {'sint0.2 DLCA'}
    {'sint0.5 BCA' }
    {'sint0.5 BPCA'}
    {'sint0.5 DLA' }
    {'sint0.5 DLCA'}
    {'sint0.7 BCA' }
    {'sint0.7 BPCA'}
    {'sint0.7 DLA' }
    {'sint0.7 DLCA'}

However, you can create matrices of indices i and j using meshgrid or ndgrid, and construct leg at once using strcat:

[i,j] = meshgrid(1:numel(Axes_name),1:numel(fold_2));
leg = reshape(strcat(Axes_name(i),{' '},fold_2(j)),[],1)
leg = 12×1 cell array
    {'sint0.2 BCA' }
    {'sint0.2 BPCA'}
    {'sint0.2 DLA' }
    {'sint0.2 DLCA'}
    {'sint0.5 BCA' }
    {'sint0.5 BPCA'}
    {'sint0.5 DLA' }
    {'sint0.5 DLCA'}
    {'sint0.7 BCA' }
    {'sint0.7 BPCA'}
    {'sint0.7 DLA' }
    {'sint0.7 DLCA'}