Creating a string with Permutation

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Chris Dan
Chris Dan 2022-7-15
回答： Voss 2022-7-15
Hi,
I have a short question, I am creating a string with a loop but I cannot do the permutation/combination correctly
here is my code
Axes_name = {'sint0.2';'sint0.5';'sint0.7'};
fold_2 = {'BCA';'BPCA';'DLA';'DLCA'};
C_ext = nan*zeros(length(Axes_name),length(fold_2));
for i=1:length(Axes_name)
for j=1:length(fold_2)
leg{sub2ind(size(C_ext),i,j)} = [Axes_name{i} ' ' fold_2{j}];
end
end
I am trying to make combinations like this:
sint0.2 BCA
sint0.2 BPCA
sint0.2 DLA
sint0.2 DLCA
sint0.5 BCA
sint0.5 BCPA
sint0.5 DLA
sint0.5 DLCA
...
and so on, but i am not getting it correctly.Does any know what changes i should do

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采纳的回答

Adam Danz
Adam Danz 2022-7-15
编辑：Adam Danz 2022-7-15
Ran in:
I believe this is what you're working toward.
Axes_name = {'sint0.2';'sint0.5';'sint0.7'};
fold_2 = {'BCA';'BPCA';'DLA';'DLCA'};
str = compose('%s %s', string(Axes_name), string(fold_2)')
str = 3×4 cell array
{'sint0.2 BCA'} {'sint0.2 BPCA'} {'sint0.2 DLA'} {'sint0.2 DLCA'} {'sint0.5 BCA'} {'sint0.5 BPCA'} {'sint0.5 DLA'} {'sint0.5 DLCA'} {'sint0.7 BCA'} {'sint0.7 BPCA'} {'sint0.7 DLA'} {'sint0.7 DLCA'}
If you want a column vector,
str(:)
ans = 12×1 cell array
{'sint0.2 BCA' } {'sint0.5 BCA' } {'sint0.7 BCA' } {'sint0.2 BPCA'} {'sint0.5 BPCA'} {'sint0.7 BPCA'} {'sint0.2 DLA' } {'sint0.5 DLA' } {'sint0.7 DLA' } {'sint0.2 DLCA'} {'sint0.5 DLCA'} {'sint0.7 DLCA'}

更多回答（2 个）

Paul
Paul 2022-7-15
Ran in:
Hi hazmah,
Is this what you're looking for?
Axes_name = string({'sint0.2';'sint0.5';'sint0.7'})
Axes_name = 3×1 string array
"sint0.2" "sint0.5" "sint0.7"
fold_2 = string({'BCA';'BPCA';'DLA';'DLCA'})
fold_2 = 4×1 string array
"BCA" "BPCA" "DLA" "DLCA"
result = reshape(Axes_name.' + " " + fold_2,[],1)
result = 12×1 string array
"sint0.2 BCA" "sint0.2 BPCA" "sint0.2 DLA" "sint0.2 DLCA" "sint0.5 BCA" "sint0.5 BPCA" "sint0.5 DLA" "sint0.5 DLCA" "sint0.7 BCA" "sint0.7 BPCA" "sint0.7 DLA" "sint0.7 DLCA"
Voss
Voss 2022-7-15
Ran in:
Axes_name = {'sint0.2';'sint0.5';'sint0.7'};
fold_2 = {'BCA';'BPCA';'DLA';'DLCA'};
You can change the size of C_ext to be length(fold_2)-by-length(Axes_name), since you want to cycle through the fold_2 values first in leg. (Swap j and i where they're used in sub2ind as well.)
C_ext = nan*zeros(length(fold_2),length(Axes_name));
for i=1:length(Axes_name)
for j=1:length(fold_2)
leg{sub2ind(size(C_ext),j,i)} = [Axes_name{i} ' ' fold_2{j}];
end
end
leg = leg.'
leg = 12×1 cell array
{'sint0.2 BCA' } {'sint0.2 BPCA'} {'sint0.2 DLA' } {'sint0.2 DLCA'} {'sint0.5 BCA' } {'sint0.5 BPCA'} {'sint0.5 DLA' } {'sint0.5 DLCA'} {'sint0.7 BCA' } {'sint0.7 BPCA'} {'sint0.7 DLA' } {'sint0.7 DLCA'}
However, you can create matrices of indices i and j using meshgrid or ndgrid, and construct leg at once using strcat:
[i,j] = meshgrid(1:numel(Axes_name),1:numel(fold_2));
leg = reshape(strcat(Axes_name(i),{' '},fold_2(j)),[],1)
leg = 12×1 cell array
{'sint0.2 BCA' } {'sint0.2 BPCA'} {'sint0.2 DLA' } {'sint0.2 DLCA'} {'sint0.5 BCA' } {'sint0.5 BPCA'} {'sint0.5 DLA' } {'sint0.5 DLCA'} {'sint0.7 BCA' } {'sint0.7 BPCA'} {'sint0.7 DLA' } {'sint0.7 DLCA'}

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