Store mxn matrix within a for loop
显示 更早的评论
How can I store results of a for loop when one iteration gives m x n matrix and not a 1 x n matrix?
a = rand(20,12);
for k=length(a)
store_this = reshape((a(k,:)), 3, [])';
end
**EDIT
The sample code I wanted to share is as follows, and the one above is wrong as pointed out :)
a = rand(20,12);
for k=1:size(a,1)
store_this = reshape((a(k,:)), 3, [])';
end
2 个评论
Rik
2022-7-19
Your loop is confusing.
Did you intend to have a single iteration?
Did you intend to use max(size(a))? Judging from your indexing, you may have wanted size(a,1) instead.
If you would have multiple iterations, that would mean your array gets overwritten every time. Is that intentional?
Jake
2022-7-19
采纳的回答
I'm not sure this is the optimal way to do it, but this does what you explain by using a cell array as an intermediary step.
a = rand(20,12);
store_this=cell(1,size(a,1));
for k=1:size(a,1)
store_this{k} = reshape((a(k,:)), 3, [])';
end
store_this=vertcat(store_this{:})
In this case your entire loop can be replaced by a single line:
x=reshape(a.',3,[]).';
isequal(x,store_this),store_this
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