matrix is singular to working precision , Contour not rendered for non-finite ZData

1 次查看（过去 30 天）
idan
idan 2022-7-21
回答： Shivam 2023-10-5
Hello,
I have read through all the trouble shooting advice on this website for the above error. I have attached my code, and I am not sure what I am doing that is causing this error.
Could somebody guide me what I am doing wornk?
Thanks.
function [] = Plot3D(cellArray,charArray)
x = linspace(-15,15,100);
y = linspace(-15,15,100);
[xx,yy] = meshgrid(x,y);
z = (sin(sqrt(xx .^2 + yy .^2)))/(sqrt(xx .^2 +yy .^2));
switch charArray
case 'surfc'
surfc(xx,yy,z);
xlabel(cellArray{2});
ylabel(cellArray{4});
zlabel(cellArray{6});
case 'surf'
surf(xx,yy,z);
grid on;
title("This is the surf:");
case 'contour'
grid on;
contour(xx,yy,z,'ShowText','on');
axis([-15 15 -15 15 -15 15]);
otherwise
subplot(2,2,1);
surfc(xx,yy,z);
subplot(2,2,2);
surf(xx,yy,z);
subplot(2,2,[3,4]);
contour(xx,yy,z);
end
  3 个评论
显示 1更早的评论
idan
idan 2022-7-21
Hello,
This is the error:
Warning: Matrix is singular to working precision.
Warning: Contour not rendered for non-finite ZData
Warning: Matrix is singular to working precision.
Warning: Matrix is singular to working precision.
Warning: Contour not rendered for non-finite ZData
Warning: Matrix is singular to working precision.
Warning: Contour not rendered for non-finite ZData
Warning: Contour not rendered for non-finite ZData
And this is the code I am trying to run:
load('cellArray.ma'); % something that I load from my computer to see if the function working.
figure('Name', 'surfc')
Plot3D(cellArray, 'surfc')
figure('Name', 'surf')
Plot3D(cellArray, 'surf')
figure('Name', 'contour')
Plot3D(cellArray, 'contour')
figure('Name', 'abc')
Plot3D(cellArray, 'abc')
Thanks.

请先登录，再进行评论。

请先登录，再回答此问题。

回答（1 个）

Shivam
Shivam 2023-10-5
Hi @idan,
As per my understanding, you are trying to make different figures using surfc, surf, contour, and plot3, where the provided code's execution is leading to warnings.
You can overcome the warnings by utilizing element-wise division instead of regular division when calculating the variable 'z.' The updated code line would look as follows:
z = (sin(sqrt(xx .^2 + yy .^2)))./(sqrt(xx .^2 +yy .^2));
I hope it helps.

类别

在 Help Center 和 File Exchange 中查找有关 Surface and Mesh Plots 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by