Obtain variable name in TLC

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Alexander Sinn
Alexander Sinn 2022-7-22
评论： Alexander Sinn 2022-7-25
I am creating a TLC file for my S-Function and I would like to produce c-code to determine the size of my vector-output-signal array via the sizeof function.
However, both LibBlockInputSignalAddr(0, "", "", 0) and LibBlockInputSignal(0, "", "", 0) only return a reference to the first element of the output signal, thus, sizeof will only return the size of one element of the corrsponding array:
sizeof testModel_Y.Outport[0]
Instead I would like to achieve:
sizeof testModel_Y.Outport
Is it possible generate this statement using a TLC file?

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采纳的回答

Andy Bartlett
Andy Bartlett 2022-7-22
Consider doing it in two parts
bytes = LibBlockInputSignalWidth(0) * sizeof( LibBlockInputSignal(0, "", "", 0) )
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Alexander Sinn
Alexander Sinn 2022-7-25
Thank you for the answer.This is the workaround I am currently using.
I was hoping to eliminate the multiplication but this seems not to be possible.

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更多回答（1 个）

Walter Roberson
Walter Roberson 2022-7-25
In C,
sizeof testModel_Y.Outport
is the size of the pointer contained in testModel_Y.Outport . Multiplying the size of one element by the number of elements is the standard way to measure size of an array in C.
  1 个评论
Alexander Sinn
Alexander Sinn 2022-7-25
According to https://docs.microsoft.com/en-us/cpp/c-language/sizeof-operator-c?view=msvc-170 above code would return the size of the array instead of the pointer: When you apply the sizeof operator to an array identifier, the result is the size of the entire array rather than the size of the pointer represented by the array identifier.
This is also in accord with my testing of this operator.

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