How to avoid a newline in sprintf
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I'm writing a code that asks to choose a subject from a list. If a subject has already been chosen in a previous run, I want the dialog box to highlight it in a caption.
However, if I use sprintf to show the number of the subject, it will print it one line below. How can I avoid it?
Bonus question: is there a way to bold the output number?
list = string(1:10);
if exist('sj', 'var') == 1
[indx,tf] = listdlg('PromptString', {'Choose a subject', ...
'(Last chosen subject:' sprintf('%d)', sj)}, ...
'ListString', list, 'SelectionMode', 'single');
else
[indx,tf] = listdlg('PromptString', {'Choose a subject'}, ...
'ListString', list, 'SelectionMode', 'single');
end
if tf == 0
return
end
sj = str2double(list(indx));
1 个评论
Stephen23
2022-7-22
"How can I avoid it?"
sprintf('(Last chosen subject: %d)', sj)
采纳的回答
sj = 3;
Consider the difference between what you have now:
{'Choose a subject', ...
'(Last chosen subject:' sprintf('%d)', sj)}
and this:
{'Choose a subject', ...
['(Last chosen subject:' sprintf('%d)', sj)]}
The first case gives you a 1x3 cell array, and the second case gives you a 1x2 cell array because the last two character vectors are concatenated using [ ]
And perhaps a more straightforward way to do it would be:
{'Choose a subject', ...
sprintf('(Last chosen subject: %d)', sj)}
2 个评论
Emilio Serani
2022-7-22
编辑：Emilio Serani
2022-7-22
Voss
2022-7-22
You're welcome, I'm not sure about making the number bold. Maybe post that as a separate question.
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