I want to draw a graph using circular layout with some nodes inside a circular layout.

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Shivanagouda Biradar 2022-7-23

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https://ww2.mathworks.cn/matlabcentral/answers/1766010-i-want-to-draw-a-graph-using-circular-layout-with-some-nodes-inside-a-circular-layout

评论： Shivanagouda Biradar 2022-7-25

s = [2 3 4 7 8];

t = [1 6 7 8 5];

G = graph(s,t);

plot(G,'Layout','circle','Center',7)

This code gives:

I want both nodes 7 and 8 inside.

How can this be done.

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回答（1 个）

Chunru 2022-7-23

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https://ww2.mathworks.cn/matlabcentral/answers/1766010-i-want-to-draw-a-graph-using-circular-layout-with-some-nodes-inside-a-circular-layout#answer_1013480

在 MATLAB Online 中打开

s = [2 3 4 7 8];

t = [1 6 7 8 5];

G = graph(s,t);

% Remove node 8 from gra[h

G1 = rmnode(G, 8);

figure;

h1 = plot(G1,'Layout','circle','Center',7);

figure;

h2 = plot(G);

h2.XData = [h1.XData(1:6) h1.XData(7)+[-.1 .1]]; % Node 7 & 8 around centre

h2.YData = [h1.YData(1:7) h1.YData(7)];

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Chunru 2022-7-24

在 MATLAB Online 中打开

I think the layout function in MATLAB has no such option. You have to manually set the node position.

s = [2 3 4 7 8];

t = [1 6 7 8 5];

G = graph(s,t);

h1 = plot(G,'Layout','circle','Center',7);

h1.XData = [cosd(90-(0:5)*60) 0.1 -0.1];

h1.YData = [sind(90-(0:5)*60) 0 0];

axis equal

Shivanagouda Biradar 2022-7-25

Thank you very much !!!!!!!!

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